The transformation (x,y) -> (x + 4,y – 3) is performed on the line segment AB.

Which of the following terms is mismatched with its example?

ryzh [129]

Answer:

b. Bias- Spring balance shows variation in measurement due to fluctuations in room temperature

Step-by-step explanation:

6 0

3 years ago

1+(-2-5)^2+(14-17)×4 please answer

hjlf

When you simplify the expression you get 38. Hope this helps.

Answer = 38.

6 0

3 years ago

Simplify. Express the quotient as a radical expression.

frez [133]

The correct answer is the first option - ninth root of x squared.
To see how I got that answer, take a look at the attachment below.

3 0

3 years ago

A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

$\chi^2_{\alpha/2}=36.191$

$\chi^2_{1- \alpha/2}=7.633$

And replacing into the formula for the interval we got:

$\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}$

$8.400 \leq \sigma^2 \leq 39.827$

So the 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

7 0

3 years ago

At store A, 3 pounds of apples cost $12. At store B, the cost is given by y = 2 x where y is the cost in dollars and x is the nu

Elina [12.6K]

Answer:

The unit price is the cost per unit of an item or the cost/price for each item.

1) 4$ per pound. By simplifying the proportion (constant ratio) between the cost, and the pounds of apples. 3 pounds of apples cost 12$ → 3/3 pounds of apples cost 12/3$ → 4 dollars for every pound.

2) 2$ per pound. By evaluating the rate of change (change in the y over x or dependent variable over independent) in the equation: y = 2x. y is the cost in dollars, and x is the pounds of apples. So there are 2 pounds (weight) of apples for every dollar.

3) 3$ per pound. Given a graph with a y scaled by 3, and an x scaled by 1 with a graph y = x or 1 unit up for every unit right. This must be equivalent to y = 3x. Where y is labeled as the cost in dollars, and x as the weight in pounds. So there are 3 dollars for every pound of apples.

4) Store B. Because 2 is less than 3 which is less than 4.

Hope it helps, stay safe and tell me if me wrong! :D

8 0

2 years ago