Answer: A volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Explanation:
Given: = 0.300 M, = ?
= 0.0450 M, = 250.0 mL
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Answer:
2523.23 cal / g
Explanation:
Mass = 6.80g
Temperature increase (T2 - T1) = 2.25
Heat capaity of calorimeter = 32.00kJK-1 = 7.64818 KcalK-1 ( Converting to calories by multiplying by 4.18)
Heat capacity = 7648.18 cal (converting to cal by mutltiplying by 1000)
Heat capacity = Heat Supplied / Temperature rise
Heat Supplied = Heat capacity * Temperature rise
Heat supplied = 7648.18 * 2.25
Heat Supplied = 17208.405 cal
To obtain the per gram value, we divide by the mass.
This gives us; 17208.405 / 6.80 = 2523.23 cal / g
Answer:
Hope this helps
Explanation:
These are called quantum numbers: there are 4, but the first three are mainly used, only in orbital notation will you use all four.
The first is the electron's energy level or "shell", used as n. (Principle QN)
The second relates to the shape of the orbital and is used as l, when n and l are put together it defines the sublevel or subshell. (Angular Momentum QN)
The third one relates to the orientation of the electrons in that sublevel used as m(sub)l. (Magnetic QN)
The fourth one relates to the spin states of the electron, since they spin opposite directions, used as m(sub)s. (Electron Spin QN)
Answer:
We are given:
V(i) = 0.3 L V(f) = 0.36 L
P(i) = x pa P(f) = 400 pa
T(i) = T(f) = 293 k
Using the gas formula:
PV = nRT
Since n , R and T are constant,
PV = k (where k is a constant)
Hence we can say that:
P(i) * V(i) = P(f) * V(f)
x * 0.3 = 0.36 * 400
x = 14.4/0.3
x = 480 pascals
Hence the initial pressure is 480 pascals
Converting to Kpa, we have to divide by 1000
Initial pressure (Kpa) = 0.48