1) Balanced chemical equation
4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g)
2) State the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Convert 88.9 g of ammonia to moles, using the molar mass
molar mass of NH3 = 14 g/mol + 3 * 1 g/mol = 17 g/mol
number of moles = mass in grams / molar mass = 88.9 g / 17 g/mol = 5.23 mol NH3
4) Make the proportion
4 mol NO / 4 mol NH3 = x / 5.23 mol NH3=> x = 5.23 mol NO
5) Convert 5.23 mol NO to grams
molar mass NO = 14 g/mol + 16g/mol = 30 g/mol
mass = number of moles * molar mass = 5.23 mol * 30 g/mol = 156.9 g ≈ 157 g
Answer: 157 grams
Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
A chemical equation is only balanced once there are equal numbers of all types of element on both sides of the equation
The person on top is very correct have a beautiful lovely day:)