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sweet-ann [11.9K]
3 years ago
14

The electronegative oxygen that is central to a water molecule is __________ bound to two hydrogen atoms. These hydrogens are 'b

ent' to form a 105° angle because _________
a.) ionically, four of the outer e- about oxygen are shared with hydrogens

b.) covalently, four of the outer e- about oxygen are shared with hydrogens

c.) covalently, of hydrogen bonding with other water molecules

d.) ionically, of hydrogen bonding with other molecules
Chemistry
1 answer:
iragen [17]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

When an atom is attached to another atom through sharing of electrons then bond formed between the atoms is known as a covalent bond. And, a bond formed by transfer of electrons from one atom to another is known as an ionic bond.

For example, electronic configuration of hydrogen is 1s^{1} and electronic configuration of oxygen is 1s^{2}2s^{2}2p^{4}. So, in order to attain stability hydrogen needs 1 more electron and an oxygen atom needs two electrons.

Therefore, two hydrogen atoms need to covalently bond through an oxygen atom leading to the formation of H_{2}O.

Thus, we can conclude that the electronegative oxygen that is central to a water molecule is covalently bound to two hydrogen atoms. These hydrogens are 'bent' to form a 105^{o} angle because four of the outer e- about oxygen are shared with hydrogens.

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If the pKa of the acid is low (negative), then the acid is strong.

Explanation:

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We defined: pKa = -log[Ka]

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Step 2: Calculate [OH⁻]

For a weak base, we will use the following expression.

[OH⁻] = √(Cb × Kb) = √(9.2 × 1.9 × 10⁻⁹) = 1.3 × 10⁻⁴ M

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