What is the frequency of a photon whose energy is 3.4 x 10-19 )? (h = 6.626 x 10-34 Js)

Chemistry

1 answer:

Tanzania [10]3 years ago

3 0

Answer:

Frequency of photon is 0.513×10¹⁵ s⁻¹

Explanation:

Given data:

Energy of photon = 3.4×10⁻¹⁹ J

Frequency of photon = ?

Planck's constant = 6.63 × 10⁻³⁴ Js

Solution:

Formula:

E = hf

3.4×10⁻¹⁹ J = 6.626 × 10⁻³⁴ Js × f

f = 3.4×10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js

F = 0.513×10¹⁵ s⁻¹

Frequency of photon is 0.513×10¹⁵ s⁻¹.

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6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)

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Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

Heat= 92.048 kJ
Mass of water = ?
Initial temperature of water= 34 ºC
Final temperature of water= 100 ºC
Specific heat of water = 4.186 $\frac{J}{gC}$

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× (100 °C -34 °C)

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× 66 °C

m= 92.048 kJ ÷ (4.186 $\frac{J}{gC}$ × 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 $\frac{g}{mole}$ , that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as: