Answer:
9.308
Explanation:
The computation of the pH of the given solution is shown below:
But before we need to determine the HI molarity which is
= 0.1852 M
Now
As we know that
So,
Now the molarity of 
left is
= 0.397 - 0.1852
= 0.2118
= 4.692
Now as we know that
pH = 14 - pOH
= 14 - pOH
= 14 - 4.692
= 9.308
We simply applied the above equations
Answer : 5.405 moles of 
are equivalent to 97.3 grams of
Solution : Given,
Mass of = 97.3 g
Molar mass of = 18 g/mole
Formula used :
or,
Now put all the given values in this formula, we get the moles of
Therefore, 5.405 moles of are equivalent to 97.3 grams of
The balanced equation for the above reaction is as follows;
CaCO₃ + 2HCl ----> CaCl₂ + H₂O + CO₂
stoichiometry of CaCO₃ to HCl is 1:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP.
volume of 22.4 L occupied by 1 mol
therefore 0.56 L occupied by - 0.56 L / 22.4 L/mol = 0.025 mol
number of HCl moles reacted - 0.025 mol
2 mol of HCl reacts with 1 mol of CaCO₃
therefore 0.025 mol reacts with - 0.025/2 = 0.0125 mol
mass of CaCO₃ required - 0.0125 mol x 100 g/mol = 1.25 g
1.25 g of CaCO₃ is required
Explanation:
answer: uuuuh so sorry if i get wrong so basically they will practice measuring different liquids. They will use a container called a graduated cylinder to measure liquids. Graduated cylinders have numbers on the side that help you determine the volume. Volume is measured in units called liters or fractions of liters called milliliters (ml).
(defently not copy and pasted)
1.67377x10-27 kilogram(kg) or 1.67377x 10-24 gram(g)
