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Vikki [24]
3 years ago
8

Can u guys help on 22. It will only take a min.

Chemistry
2 answers:
Anni [7]3 years ago
7 0

Answer:

Alpha > beta>gamma

Explanation:

Comparing only the three common types of ionizing radiation, alpha particles have the greatest mass. Alpha particles have approximately four times the mass of a proton or neutron and approximately 8,000 times the mass of a beta particle.

Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.

Dahasolnce [82]3 years ago
3 0

Answer:

\boxed {\boxed {\sf Gamma, beta, alpha}}

Explanation:

Alpha. beta, and gamma particles are all emitted from an unstable or radioactive nucleus during radioactive decay.

  • Alpha particles are essentially helium ions, made of 2 protons and 2 neutrons. It has an atomic mass of 4 atomic mass units.

  • Beta particles are also known as electrons. They have masses of 1/1840 atomic mass units.

  • Gamma particles are actually just rays or photons of electronegative energy emitted. They have no mass or a mass of 0 atomic mass units.

So, if we place the mass in increasing order (least to greatest), then it is <u>gamma (0 amu), beta (1/1840 amu) and alpha (4 amu).</u>

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Alex777 [14]

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\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅,  then convert to molecules of P₂O₅.

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\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}

2. Moles of P₂O₅

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The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}

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\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}

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During oxidation, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g
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6 0
3 years ago
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