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Mrac [35]
3 years ago
8

What is the equation of the line that is parallel to the line defined by the equation y = 3x + 6 and goes through the point (3,

2)?
options:
y = 2x – 1
y = 3x – 7
y = 2x + 4
y = 4x + 3
y = -2x + 9
Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Parallel lines have the same slope. The slope of the given line is 3. The easy way to do this, the one that uses our logical brains as opposed to our mathematical brain, tells us that since there is only one choice that has a given slope of 3, that is the one that we want. The second choice down is the only one that has a slope of 3.

Mathematically,

y-2=3(x-3) and

y-2=3x=9 and

y=3x-9+2 so

y = 3x - 7 (the second choice)

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Vanyuwa [196]

Answer: 1: Given

2: Distribution

3: Subtraction

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Step-by-step explanation:

6 0
3 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
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A company makes steel rods shaped like cylinders. Each rod has a radius of 4 centimeters and a height of 20 centimeters. If the
Tamiku [17]
(One steel rod’s volume) = 3.14 x 4^2 x 20

= 1004.8cm^3

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2 years ago
Use the graph of y=e^x to evaluate the expression e^-2.8 round the solution to the nearest tenth if necessary
ICE Princess25 [194]
In this item, I assume that the variable "e" here stands for the Euler number which is equal to 2.718. Raising this number to the exponent -2.8 will give us an answer of, 
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Therefore, the value of y is approximately 0.1. 
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3241004551 [841]

Answer:

5, 5, 5

Step-by-step explanation:

i saw it on quizlet

5 0
3 years ago
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