This is an arithmetic sequence with the common difference being 1
and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..
the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40
now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum
Hello from MrBillDoesMath!
Answer: (4b-6) log(a) = log (3c + d)
Discussion:
Take the log of both sides of the equation:
log ( a ^(4b-6)) = log (3c + d)
As the log functions causes exponents to become multiplexers, this equation is the same as
(4b-6) log(a) = log (3c + d)
Thank you,
MrB
Answer:
Step-by-step explanation:
Given
on Sales over 50000
Required
Determine the function j(s) for sales over 50000
Represent the total sales in a month with s.
Sales over 50000 in that month will be: s - 50000
So, the function j(s) is:
j(s) = Base Amount + Commission * Sales over 50000
Convert % to decimal
Open bracket
Collect Like Terms
12 16/56 + 3 35/56 = 15 51/56
Answer:
In a tape diagram, each of the lengths represents a fixed quantity of something.
Let's suppose that each one of these lengths represents a distance d.
We also know that the expert trail is 750 meters longer than the beginner one.
And in the tape diagram, the expert trail has 3 more lengths than the beginner trail, then we must have that the difference in distance must be equivalent with the difference in lengths.
750m = 3*d
d = 750m/3 = 250m
Then each length in the tape diagram represents 250m
With this we can find the length of each trail.
The beginner trail has 1 length, then it is 1*250m = 250 meters long.
The expert trail has 4 lengths, then it is 4*250m = 1000 meters long.
