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Blizzard [7]
3 years ago
9

What is the correct factorization of

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

<em><u>(x</u></em><em><u>-</u></em><em><u>1)(x</u></em><em><u>+</u></em><em><u>6)</u></em>

Step-by-step explanation:

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The number of cases of a new diease can be modeled by the quadratic
Arada [10]

Step-by-step explanation:

The number of cases of a new disease may be modeled by the quadratic regression equation y=-2x^2+44x+8 , what is the best prediction for the number of cases after 20 years ( the carrot symbol (^) means the following number is the exponent)

5 0
2 years ago
The decorating committee for a
Sonja [21]
160 flowers
The ratio is 3:5 of white to yellow.
They need 60 white which means they times by 20. So 20x5=100 they will need 100 yellow. In total they need 160
8 0
3 years ago
Enter the value of w so the expression -5 +0.6W is equivalent to w (2.5 – 0.3w)​
NeX [460]

9514 1404 393

Answer:

  w = -2 or 8 1/3

Step-by-step explanation:

Setting the two expressions equal makes a quadratic equation:

  -5 +0.6w = w(2.5 -0.3w)

  0.3w^2 -1.9w -5 = 0 . . . . . . subtract the right-side expression

  3w^2 -19s -50 = 0 . . . . . . . multiply by 10 to give integer coefficients

  (3w -25)(w +2) = 0 . . . . . . . factor

We can use the zero product rule to find the solutions. The product will be zero only if a factor is zero.

  3w -25 = 0   ⇒   w = 25/3 = 8 1/3

  w +2 = 0   ⇒   w = -2

The values of w that make the two expressions equivalent are -2 and 8 1/3.

8 0
2 years ago
Which is an example of an expression?<br> O 3,2 – 4.<br> O a = 144<br> 0 10 = 2.5<br> O 2 &lt; 52
cluponka [151]

Answer:

2 - 4

Step-by-step explanation:

no equal sign

4 0
2 years ago
Determine whether the three points are collinear.<br> (0, - 10). (-3,- 13), (2,-8)
LUCKY_DIMON [66]

Answer:

<h2>YES. These points are collinear.</h2>

Step-by-step explanation:

If three points are collinear, then the slopes are the same.

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

For (0, -10) and (-3, -13):

m=\dfrac{-13-(-10)}{-3-0}=\dfrac{-13+10}{-3}=\dfrac{-3}{-3}=1

For (-3, -13) and (2, -8):

m=\dfrac{-8-(-13)}{2-(-3)}=\dfrac{-8+13}{2+3}=\dfrac{5}{5}=1

We can check the last pair (0, -10) and (2, -8):

m=\dfrac{-8-(-10)}{2-0}=\dfrac{-8+10}{2}=\dfrac{2}{2}=1

5 0
3 years ago
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