What do you mean? I’m not sure
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
<em>options: A,C,E </em>are correct.
Step-by-step explanation:
We have to find the expression equivalent to the expression:
we know that: 
Hence,
-----(1)
A) 
(same as(1))
Hence, option A is correct.
B) 7 ; which is a different expression from (1)
Option B is incorrect.
C) 
(Same as (1))
Option C is correct.
D) 
which is a different expression from (1)
Hence, option D is incorrect.
E) 
; which is same as (1)
Hence, Option E is correct.
F) 
; which is not same as expression (1)
Hence, option F is incorrect.
Answer:
20 <u>></u> 8+3g
Step-by-step explanation:
3/7 or 3:7 because you tossed the dice 7 times and got an even number 3 of those times.
