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beks73 [17]
3 years ago
8

Yolanda spends 8 2⁄3 hours per month playing soccer. Approximately how many hours does she play soccer in a year? (There are twe

lve months in a year.) A. 416 B. 104 C. 197 D. 28
Mathematics
1 answer:
Anna11 [10]3 years ago
7 0
The answer is: B

This problem will only need simple multiplication...

Answer = number of hours per months * months in a year

= 8 2/3 hours / month * 12 months
= 104 hours in 1 year
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Suppose that 5 cards are drawn from a well-shuffled deck of 52 cards. What is the probability that all 5 are not black?
lions [1.4K]
Here's the way I see it:  5 cards are drawn, one by one, without replacement.  Half (or 26) of the original deck are black and half (26) are white.

P(5 are not black) = P(5 are red)

P(5 are not black) = P(first card is red) * P(second card is red) * P(third card is red)*P(fourth card is red)*P(fifth card is red) =

(26/52) * (25/51) * (24/50) * (23/49) * (22/48) = 0.025   (answer)

We start with 52 cards.  We draw one, leaving 51 cards, 25 of which are red.  And so on.
6 0
3 years ago
Please can you help me with this problems. Thanks.
KengaRu [80]
1. Pants=2, shirts= 3
# outcomes 2*3=6

2. Flavors=3, toppings= 4
# outcomes 3*4= 12

3. Type=3, color=3
# outcomes 3*3= 9
4 0
3 years ago
Read 2 more answers
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
Evaluate 3xy with an exponent of 2 y, if x=2 and y=5
Bogdan [553]

Answer:

145

Step-by-step explanation:

x = 2 , y= 5

Putting the values of x and y in the expression

=3(2) (5)^2-5

=3(2)(25)-5

=150 -5

=145

8 0
3 years ago
What is the value of x
Lilit [14]

Answer:

4

Step-by-step explanation:

For the first triangle which is triangle <KJL

Hypotenuse= 8✓2

Angle=30°

Opposite = ?

Therefore we will use Sine formula

Sin30° = Y/8✓2

Y=4✓2

For the second triangle which is triangle <JML

Hypotenuse= 4✓2

Opposite=X

Angle=45°

Therefore we will use Sine formula again

Sin45°=X/4✓2

X=4

3 0
3 years ago
Read 2 more answers
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