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2 years ago

If an object is moving right at 10 N and a force is applied from the left at 8N, what is the net force on the object?

Chemistry

1 answer:

ryzh [129]2 years ago

5 0

Answer:

If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

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D.) It cannot be broken down into a simple substance through chemical means...

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What is the relationship between the concentration of particles in a solution and the solution’s vapor pressure? As solute conce

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Answer:

As solute concentration increases, vapor pressure decreases.

Step-by-step explanation:

As solute concentration increases, the number of solute particles at the surface of the solution increases, so the number of solvent particles at the surface decreases.

Since there are fewer solvent particles available to evaporate from the surface, the vapour pressure decreases.

C. and D. are wrong. The vapour pressure depends only on the number of particles. It does not depend on the nature of the particles.

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3 years ago

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Verdich [7]

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2 years ago

200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486

ololo11 [35]

The empirical formula of a given compound is C6H9ON5.

Explanation:

Step 1: Obtain the mass of each element present in grams

Element % = mass in g = m

Carbon = 83.884 grams, Hydrogen = 10.486 grams, Oxygen = 18.640 grams, Nitrogen = 86.99 grams.

Step 2: Determine the number of moles of each type of atom present

m/atomic mass = Molar amount (M)

Molar amount of carbon = (83.884 1 mol ) / 12 g = 6.99

Molar amount of hydrogen = (10.486 1 mol) / 1 g = 10.49

Molar amount of oxygen = (18.64 1 mol) / 16 g = 1.17

Molar amount of nitrogen = (86.99 1 mol) / 14 g = 6.21

Step 3: Divide the number of moles of each element by the smallest number of moles

M / least M value = Atomic Ratio (R)

Atomic radius of carbon = 6.99 / 1.17 = 5.9 = 6

Atomic radius of hydrogen = 10.49 / 1.17 = 8.9 = 9

Atomic radius of oxygen = 1.17 / 1.17 = 1

Atomic radius of nitrogen = 6.21 / 1.17 = 5

Step 4: Convert numbers to whole numbers. This set of whole numbers are the subscripts in the empirical formula.

R * whole number = Empirical Formula

The empirical formula of a given compound is C6H9ON5.

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