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A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

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3 0

2 years ago

Determine what mass of carbon monoxide and what mass of hydrogen are required to form 6.0 kg of methanol by the reaction CO(g) +

siniylev [52]

Answer:

5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

Explanation:

The balanced reaction:

CO (g) + 2 H₂ (g) -> CH₃OH (l)

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

CO: 1 mole
H₂: 2 moles
CH₃OH: 1 mole

Being the molar mass of each compound:

CO: 28 g/mole
H₂: 1 g/mole
CH₃OH: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CO: 1 mole* 28 g/mole= 28 grams
H₂: 2 moles* 1 g/mole= 2 grams
CH₃OH: 1 mole* 32 g/mole= 32 grams

Being 6 kg equivalent to 6000 grams (1 kg= 1000 grams), you can apply the following rules of three:

If by stoichiometry 32 grams of methanol are formed from 28 grams of carbon monoxide, 6000 grams of methanol are formed from how much mass of carbon monoxide?

$mass of carbon monoxide=\frac{6000 grams of methanol*28 grams of carbon monoxide}{32 grams of methanol}$

mass of carbon monoxide= 5250 grams= 5.25 kg

If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?

$mass of hydrogen=\frac{6000 grams of methanol*2 grams of hydrogen}{32 grams of methanol}$

mass of hydrogen= 375 grams

<u><em>5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol. </em></u>

8 0

3 years ago

A chemist prepares a solution of vanadium chloride by measuring out of into a volumetric flask and filling to the mark with dist

user100 [1]

The question is incomplete, the complete question is:

A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.

Answer:

0.153M of anions

Explanation:

First we calculate the concentration of the solution. From m/M= CV

m=given mass, M= molar mass, C =concentration of solution, V= volume of solution

Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1

0.4g/157.5gmol-1= C×50/1000

C= 2.54×10-3/0.05= 0.051M

But 1 mole of VCl3 contains 3 moles of anions

Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions

4 0

3 years ago

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