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statuscvo [17]
3 years ago
15

Ethanol can react with hydrochloric acid to form chloroethane and water. When sulfuric acid is added, the

Chemistry
1 answer:
kaheart [24]3 years ago
6 0

Answer: 1.Sulfuric acid is a catalyst

2. Vanadium(v) oxide is a catalyst

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Calcutale Grxn for the following equation at 25°C: <br><br> 4KClO3(s) → 3KClO4(s) KCl(s)
Step2247 [10]

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

5 0
4 years ago
Which best defines nitrogen fixation
arlik [135]

Answer: the conversion of nitrogen gas into a usable form

Explanation: its a process that bacteria converts nitrogen gas into a usable form

5 0
3 years ago
2. (Exercise 4.1.6) A liquid adhesive consists of a polymer dissolved in a solvent. The amount of polymer in the solution is imp
Lilit [14]

Answer:

800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

Explanation:

3000 lb of 13% solution is required .

Total adhesive in weight = 3000 x .13 = 390 lb of adhesive

Available = 500 lb of 10% solution = 50 lb of adhesive

Rest = 390 - 50 = 340 lb required .

rest mass of solution = 3000 - 500 = 2500 lb

mass of adhesive required = 340 lb

Let the mass  of 20% required be V

mass of adhesive = .20 V

.20 V = 340

V = 1700

rest of the volume = 2500 - 1700 = 800 lb which will be of pure solvent

So 800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

6 0
4 years ago
given a mixture of lead to oxide ammonium chloride and sodium chloride describe how a mixture can be separated to obtain a sampl
wariber [46]

Answer:

There are way in separating mixtures of chloride salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration, and sublimation. The easiest method among the three is separation by sublimation.

5 0
3 years ago
A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
jeyben [28]

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

4 0
3 years ago
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