According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is
The answer is:
Transverse dune
The explanation:
Transverse dune : is abundant barchan dunes It may merge into barchanoid ridges, which then grade into linear .
The transverse dunes is called that because they lie transverse, or across, the wind direction, with the wind blowing perpendicular to the ridge crest.
It is large, very asymmetrical, elongated dune lying at right angles 90° to the prevailing wind direction.
Transverse dunes have a gently sloping windward side and a steeply sloping leeward side.
They general form in areas of sparse vegetation and abundant sand are transverse dunes.
Answer:
7.5 right?
Explanation: if im wrong shoot me
A customer is billed for a service or product, but it gets recorded in the ledger at a lower amount is an example of fraudulent bookkeeping on the income side. This fraud would likely happen in the account receivable department of a company which generates sales for its function<span>. The sale is the primary source of company's operational income.</span>
Answer:
v = 6t² + t + 2, s = 2t³ + ½ t² + 2t
59 m/s, 64.5 m
Explanation:
a = 12t + 1
v = ∫ a dt
v = 6t² + t + C
At t = 0, v = 2.
2 = 6(0)² + (0) + C
2 = C
Therefore, v = 6t² + t + 2.
s = ∫ v dt
s = 2t³ + ½ t² + 2t + C
At t = 0, s = 0.
0 = 2(0)³ + ½ (0)² + 2(0) + C
0 = C
Therefore, s = 2t³ + ½ t² + 2t.
At t = 3:
v = 6(3)² + (3) + 2 = 59
s = 2(3)³ + ½ (3)² + 2(3) = 64.5
