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ArbitrLikvidat [17]
3 years ago
14

Long sand ridges oriented at right angles to the wind are called _____ dunes

Physics
2 answers:
S_A_V [24]3 years ago
3 0

The answer is:

Transverse dune

The explanation:

Transverse dune : is abundant barchan dunes It  may merge into barchanoid ridges, which then grade into linear .

The transverse dunes is called that because they lie transverse, or across, the wind direction, with the wind blowing perpendicular to the ridge crest.

It is large, very asymmetrical, elongated dune lying at right angles 90° to the prevailing wind direction.

Transverse dunes have a gently sloping windward side and a steeply sloping leeward side.

They general form in areas of sparse vegetation and abundant sand are transverse dunes.

dsp733 years ago
3 0
Transverse dunes comment if wrong
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Analyze the following terms and phrases about solar activity. Select the two that represent correct matches between cause and ef
blagie [28]

Answer:

a) solar activity -- sudden eruptions of large bubbles of plasma and magnetic energy

and

d) solar flare -- sudden release of magnetic energy

Explanation:

We can start by eliminating the options that are definitely wrong.

A coronal mass ejection is not a relatively cool spot on surface of the sun, in fact such a spot is a sunspot, while a coronal mass ejection occurs when the  magnetic field of the sun emerges as a loop. Thus, both options B and E are incorrect, leaving only A,  C, and D. Option C makes no sense, as the sun's gravitational field does not 'churn'. Thus, only options A and D are left. A closer look at A and D reveals they are correct; solar flares are in fact sudden releases of magnetic energy, as seen in this quote from UC Berkeley's website; "Solar flares are caused by sudden changes of strong magnetic fields in the Sun's corona.". And solar activity is a blanket term for the effects of eruptions of plasma and magnetic energy from the sun.

7 0
3 years ago
Is hydrogen energy renwable? Why<br> How is it used nowadays<br> How is it obtained?
hram777 [196]

Answer:

t

Explanation:

5 0
2 years ago
NO LINKS
zhenek [66]

Answer: A , D & F

Explanation:

6 0
2 years ago
Calculate the kinetic energy in joules of an automobile weighing 2135 lb and traveling at 55 mph. (1 mile = 1.6093 km, 1 lb = 45
victus00 [196]
<span>Let's convert the speed to m/s: speed = (55 mph) (1609.3 m / mile) (1 hour / 3600 seconds) speed = 24.59 m/s Let's convert the mass to kilograms: mass = (2135 lb) (0.45359 kg / lb) mass = 968.4 kg We can find the kinetic energy KE: KE = (1/2) m v^2 KE = (1/2) (968.4 kg) (24.59 m/s)^2 KE = 292780 joules The kinetic energy of the automobile is 292780 joules.</span>
4 0
3 years ago
A spring with a spring constant of 2500 n/m. is stretched 4.00 cm. what is the work required to stretch the spring?
Yuri [45]
W = 1/2k*x^2.

k = spring constant = 2500 n/m.
x = distance = 4 cm = 0.04m (convert to same units).

W = 1/2(2500)(0.04)^2 = 2J.
5 0
3 years ago
Read 2 more answers
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