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3 years ago

A.

Mathematics

2 answers:

Tamiku [17]3 years ago

3 0

Answer:

Step-by-step explanation:

A function is a relation that associates each element x of a set X, to a single element y of another set Y.

In D) for x = 0 we have three values of y = f(x): -1, 4 and 6.

Therefore this table does not represent a function.

just olya [345]3 years ago

3 0

Answer:

for the first graph it is

a=1

b= 1/16

c=1/256

for the second graph it is

d=1

e=4/9

f=16/81

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9 times 10 to the fourth power

laiz [17]

Someone deleted my answer but if you need to look back its 90000

4 0

3 years ago

A variable needs to be eliminated to solve the system of equations below. Choose the

notsponge [240]

Answer:

x=-2

y= 8

Step-by-step explanation:

Given data

10x – 2y = -36-----------1

7x – 2y = -30--------------2

-Subtract to eliminate y

3x-0= -6

3x= -6

x= -6/3

x= -2

Put x= -2 in

7(-2)– 2y = -30

-14-2y=-30

-14+30=2y

16=2y

y= 16/2

y= 8

8 0

3 years ago

If f(x) is a function and f(1) = 5, then which of the following could not be true?

vodomira [7]

A. you are given that f(1)=5 therefore f(1) cannot also equal 1 unless it is a different equation.

5 0

3 years ago

The area of a mirror is 225 Square inches, it's width is

Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

<em><u>Solution:</u></em>

Given that area of mirror is 225 square inches

$width = 13\frac{3}{4} \text{ inches }$

Converting the above mixed fraction we get,

$width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }$

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

$225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36$

Thus length of mirror is 16.36 inches

<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is $\frac{55}{4} = 13.75$ inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

7 0

3 years ago

The median of 50 50 54 56 60 62 63 64 79 72 72

miss Akunina [59]

Answer:

Step-by-step explanation:

50,50,54,56,60,62,63,64,79,72,72,

median ids the number at the center

50,50,54,56,60(62)63,64,79,72,72

3 0

3 years ago