In this question, we're trying to find how much Paul will pay per month in premiums.
We know that the plan costs $7,710 for a year
In order to find his premium cost per month, we need to get the total price for the year and divide it by 12, since there are 12 months in a year.
Solve:
7,710 ÷ 12 = 642.50
This means that he'll pay $642.50 a month.
Answer:
$642.50
Answer:
GK=JK
Step-by-step explanation:
SSS congruency is side-side-side congruency. We are given that GH=JH and KH=KH, which are both sides.
For SSS, we need 3 pairs of congruent sides. We already have 2 pairs.
The options are:
<G=<J
<H=<H
GK=JK
the first two options, <G=<J and <H=<H are talking about congruent angles. We don't need to know about congruent angles for SSS
GK=JK is talking about a pair of congurent sides. Then, we would have 3 pairs of congruent sides, satisfying the criteria needed for SSS. Therefore, we must know that GK=JK.
Hope this helps!
Answer:im pretty sure its 64.8
Step-by-step explanation:
Answer:
a = 3
b = 2
c = 0
d = -4
Step-by-step explanation:
Form 4 equations and solve simultaneously
28 = a(2)³ + b(2)² + c(2) + d
28 = 8a + 4b + 2c + d (1)
-5 = -a + b - c + d (2)
220 = 64a + 16b + 4c + d (3)
-20 = -8a + 4b - 2c + d (4)
(1) + (4)
28 = 8a + 4b + 2c + d
-20 = -8a + 4b - 2c + d
8 = 8b + 2d
d = 4 - 4b
Equation (2)
c = -a + b + d + 5
c = -a + b + 4 - 4b+ 5
c = -a - 3b + 9
28 = 8a + 4b + 2c + d (1)
28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b
28 = 6a - 6b + 22
6a - 6b = 6
a - b = 1
a = b + 1
220 = 64a + 16b + 4c + d (3)
220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b
220 = 60b + 100
60b = 120
b = 2
a = 2 + 1
a = 3
c = -3 - 3(2) + 9
c = 0
d = 4 - 4(2)
d = -4
Step by step. :)
STEP
1
:
Equation at the end of step 1
0 - 7n • (n - 7) = 0
STEP
2
:
Equation at the end of step 2
-7n • (n - 7) = 0
STEP
3
:
Theory - Roots of a product
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
3.2 Solve : -7n = 0
Multiply both sides of the equation by (-1) : 7n = 0
Divide both sides of the equation by 7:
n = 0
Solving a Single Variable Equation:
3.3 Solve : n-7 = 0
Add 7 to both sides of the equation :
n = 7
This is what i got! if i’m wrong i’m so sorry
but i tried. have a amazing day☺️☺️
