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sertanlavr [38]
3 years ago
14

claire thinks that if she draws a parallelogram with 2 congruent sides, it must be a rhombus. Jacob that she would need to draw

a parallelogram with at least 3 congruent sides before she could be sure it was a rhombus. who is correct, if anyone, and why?
Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer with explanation:

A rhombus has all sides equal that is four congruent sides.

Statement of Claire

 If she draws a parallelogram with 2 congruent sides, it must be a rhombus.

As Rhombus has four Congruent sides.2 Congruent sides does not Guarantee that the Parallelogram will be Rhombus.If Adjacent sides are congruent than Claire statement will be right otherwise not.

Statement of Jacob

If Jacob draws a parallelogram with at least 3 congruent sides ,it must be a rhombus.

Yes ,three congruent sides Guarantees that Parallelogram will be a rhombus because in a Parallelogram opposite sides are equal to each other.So congruency of three sides in a Parallelogram guarantees that this Parallelogram will be a rhombus.

So, we can Conclude that Jacob is correct.

PSYCHO15rus [73]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

Neither are correct:  a parallelogram with 3 congruent sides could be a square. Also a parallelogram will  have 2 pairs of congruent sides  but it does not have to be a rhombus.

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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill
abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}

To find A and k

V(0) = A = 3 million

Hence V = 3e^{kt}

V(6) = 1.5

i.e. 1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552

V(t) = 3e^{-0.11552t}

a) Using the above value of k , we have

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year.

4 0
3 years ago
So I have another trigonometry question PLZ HELP ME I'm clueless at this rate I have like a little idea but I'm lost, SO PLZZZ!
Sergio039 [100]

Answer:

1) The windsurfer is approximately 580 ft from each lifeguard stand.

2) The distance between the Earth and Mercury is approximately 61 million miles.

Step-by-step explanation:

The image other two situations described is presented in the attached image to this answer.

1) From the attached image, the windsurfer forms a right angled triangle with each of the lifeguard stand and the midpoint between the two lifeguard stands.

Hence, the angle at the top of the triangle is half of 30°, 15° and the distance from the midpoint of the lifeguard stands to the lifeguard stands is 300/2 = 150 ft.

Let the required distance of the windsurfer from each of the lifeguard stands be x.

Using trigonometric relations,

Sin 15° = (150/x)

x = 150 ÷ sin 15° = 150 ÷ 0.2588

x = 579.6 ft = 580 ft to the nearest whole number

2) From the image, the Sun, Earth and Mercury form a triangle.

Let the possible distance between the Earth and Mercury be y.

Using cosine rule,

y² = 36² + 93² - (2×36×93×cos 22°)

y² = 3,736.5769098208

y = √3,736.5769098208 = 61.13 million miles = 61 million miles to the nearest million miles.

Hope this Helps!!!

5 0
2 years ago
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hammer [34]

Answer: 3

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6 0
2 years ago
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Free_Kalibri [48]
The answer is D, Surface area
7 0
3 years ago
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tankabanditka [31]
It would be t=0.8, mainly bc you subtract two from six , that reduces it to four 
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