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frez [133]
3 years ago
13

Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0
ANSWER

D.
A=3,P=2\pi,PS=(4,9)

EXPLANATION

The given function is

f(x) = 3 \sin(x - 4) + 9

Comparing to the general form of a trigonometric sine function,

f(x) = A \sin(Bx-C)+D

A=3
The amplitude is absolute value of A

|A| = |3| = 3

B=1

The period is given by

p = \frac{2\pi}{ B}

p = \frac{2\pi}{ 1} = 2\pi

C=4

is a shift to the right of 4 units.

and

D=9

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D
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