Question

Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9

Answer 1

ANSWER

D.
$A=3,P=2\pi,PS=(4,9)$

EXPLANATION

The given function is

$f(x) = 3 \sin(x - 4) + 9$

Comparing to the general form of a trigonometric sine function,

$f(x) = A \sin(Bx-C)+D$

$A=3$
The amplitude is absolute value of A

$|A| = |3| = 3$

$B=1$

The period is given by

$p = \frac{2\pi}{ B}$

$p = \frac{2\pi}{ 1} = 2\pi$

$C=4$

is a shift to the right of 4 units.

and

$D=9$

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D