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RoseWind [281]
3 years ago
6

A point is randomly chosen in the diagram shown below. What is the likelihood that a point chosen inside the square will also be

inside the circle?

Mathematics
2 answers:
spayn [35]3 years ago
8 0
78.54% your welcome
s2008m [1.1K]3 years ago
3 0
Side of the square: s
Area of the square: As=s^2

Diameter of the circle: d=s
Area of the circle: Ac=pi d^2/4
Ac=pi s^2/4; pi=3.1416
Ac=3.1416 s^2/4
Ac=0.7854 s^2

<span>The likelihood that a point chosen inside the square will also be inside the circle: P=?
P=Ac/As=0.7854 s^2 / s^2
P=0.7854
P=0.7854 * 100%
P=78.54%

</span>The likelihood that a point chosen inside the square will also be inside the circle is 0.7854 or 78.54%
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trasher [3.6K]

Answer:

I'm not entirely sure what the question is but every thing under 12.5 is closer to 12, everything 12.5 and upwards like 12.87 would be closer to 13

8 0
2 years ago
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3 0
3 years ago
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I'll give more points here is what I need.
Serga [27]

Answer:

The answer to your question is x = 3; y = 3

Step-by-step explanation:

Data

angle = 45°

Opposite side = x

Adjacent side = y

hypotenuse = 3√2

To solve this problem, use trigonometric functions.

1) To find x, use the trigonometric function sine.

              sin Ф = Opposite side / hypotenuse

-Solve for Opposite side (x)

              Opposite side = hypotenuse x sin Ф

-Substitution

              Opposite side = 3√2 sin 45

-Simplification

               Opposite side = 3√2 (1 / √2)

               Opposite side = 3(1)

-Result  

               x = 3

2) To find y use the trigonometric function cosine

               cos Ф = Adjacent side / hypotenuse

-Solve for Adjacent side

                Adjacent side = hypotenuse x cos Ф

-Substitution

                Adjacent side = 3√2 x cos 45

-Simplification

                Adjacent side = 3√2 x (1/√2)

                Adjacent side = 3(1)

-Result

                y = 3

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dybincka [34]
The correct answer is
#2x^(-1/2)
8 0
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