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Margarita [4]
3 years ago
15

Can anyone rewrite the quadratic function in standard form?

Mathematics
1 answer:
ycow [4]3 years ago
3 0

Answer:

So we first open multiply the parenthesis by 9. 9x+5 is what it is. Now we need to simply it even more with the 2 parenthesis

(9x+5)(x+1) = 9x^2+9x+5x+5 = 9x^2+14x+5

<h2><u>Answer: 9x^2+14x+5</u></h2>

You might be interested in
Find the 11th term of the arithmetic sequence an=<br> 24 – 7(n - 2)<br> 2115
sweet [91]

Answer:

Let's simplify

24−7(n−2)(2115)

Step-by-step explanation:

step-by-step.

=−14805n+29634

I hope my answer helped

7 0
2 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
I don't know i just need help with this quiz ok
ololo11 [35]
The answer is 73....
5 0
3 years ago
Write an expression for the sequence of operations. <br> Subtract 4 from x, double, and add 8.
Ivenika [448]
4-x=3
Double the 3 witch is =6
And add 8 witch is
6+8=14
3 0
3 years ago
Please help me with this
zhannawk [14.2K]
I’m pretty sure it’s 82
6 0
2 years ago
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