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Margarita [4]
3 years ago
15

Can anyone rewrite the quadratic function in standard form?

Mathematics
1 answer:
ycow [4]3 years ago
3 0

Answer:

So we first open multiply the parenthesis by 9. 9x+5 is what it is. Now we need to simply it even more with the 2 parenthesis

(9x+5)(x+1) = 9x^2+9x+5x+5 = 9x^2+14x+5

<h2><u>Answer: 9x^2+14x+5</u></h2>

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What is 1+1? 10 point if u get it right.
kap26 [50]

Answer:

11

Step-by-step explanation:

duh add 1 and 1 merge it together to get 11

5 0
2 years ago
Read 2 more answers
A pan of lasagna cut into 100 servings is equally shared among a group of people. For Exercises
Volgvan

53).  100 servings / 20 people  =  (100/20) (svngs/ppl)

                                                 = 5 servings per person.

         Each person gets 1/20 = 5% = 0.05 of the pan.


54).  100 servings / 40 people  =  (100/40) (svngs/ppl)

                                                 = 2.5 servings per person.

         Each person gets  1/40 = 2.5% = 0.025 of the pan.


55).  100 servings / 30 people  =  (100/30) (svngs/ppl) 

                                                  = (3 and 1/3) servings per person.

         Each person gets  1/30 = (3 and 1/3) % = 0.0333... of the pan.
 
3 0
3 years ago
Help me on question 9
gogolik [260]

Answer:

C

Step-by-step explanation:

The problen asks for 5 more than two times n. 2 times n suggests multiplication. So we start out with 2n. When it says 5 more it suggests addition. So we end up with 2n+5

7 0
3 years ago
Read 2 more answers
Show your work plz luv u
atroni [7]

Answer:

x=7

Step-by-step explanation:

Step 1: Subtract 4x from both sides.

x+30−4x=4x+9−4x

−3x+30=9

Step 2: Subtract 30 from both sides.

−3x+30−30=9−30

−3x=−21

Step 3: Divide both sides by -3.

−3x

−3

=

−21

−3

<u><em>The sides of a rhombus are all congruent (the same length.)</em></u>

6 0
3 years ago
A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times. Let x¯1 represent the average of the
Anna35 [415]

Answer:

option B

Step-by-step explanation:

P(x =x) [{\frac{1}{6} ;x =1,2,3...6]

E (x) = \frac{6+1}{2} =\frac{7}{2} =3.5\\\\E(x)=3.5

Given random experiment of tossing of 6 sided dice is follow above distribution

Therefore, suppose x₁, x₂ ...x₁₀ are 10 independent and indentical random variable which represent first 10 rolls

Average of first 10 rows equals

\bar x_1 =\frac{ \sum ^{10}_{i=1}xi}{10}

E(\bar x_1)=\frac{ \sum ^{10}_{i=1}E(x_1)}{10} \\\\=\frac{10(3.5)}{10} \\\\=3.5\\\\E(\bar x_1) = 3.5----(1)

now suppose ,

x₁₁,x₁₂, ...x₁₅ are 5 independent and identical random variable which represent last 5 roll

average of last 5 roll is

E(\bar x_2)= \frac{ \sum ^{5}_{i=1}xi}{5} \\\\= \frac{5 \times(3.5)}{5} \\\\=3.5

Therefore,\bar x_1 - \bar x_2

3.5 - 3.5 = 0

5 0
3 years ago
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