Question

What is the magnetic force on a proton that is moving at 4.5 107 m/s to the right through a magnetic field that is 1.6 T and pointing away from you? The charge on a proton is 1.6 10-19 C. Use F = qv B sin.
A. 7.2 10^-7 N down
B. 1.2 10^-19 N down
C. 1.2 10^-11 N up
D. 7.2 10^-7 N up

Answer 1

The answer is letter C. 1.2 10^-11 N up
Solution:
F= Bqvsin(theta)
theta = sin 90 = 1
F= 1.4 T * 1.6x10^-19 * 5.2x10^7 ms^-1
F= 1.16 x 10^-11 N
Then the direction is upward.

Answer 2

C) 1.2•10^-11 N up

is the answer