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Arte-miy333 [17]
3 years ago
9

Which of the following are Electromagnetic Waves?

Physics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

b

Explanation:

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A 75.0 kg object decelerates from a speed of 100 m/s to 50 m/s over an interval of 25 seconds. What was the net force acting upo
lukranit [14]

Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of

<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²

Then the net force has a magnitude <em>F</em> such that, by Newton's second law,

<em>F</em> = (75.0 kg) <em>a</em>

<em>F</em> = (75.0 kg) (-2 m/s²)

<em>F</em> = -150 N

meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.

7 0
4 years ago
Fig. 2.1 shows a train
Vitek1552 [10]

Answer:

\mathrm{(a)\:}32,000,000\:\mathrm{Ns},\\\mathrm{(b)\:}390,000\:\mathrm{N}

Explanation:

The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by p=mv. Since mass is constant, the train's change in momentum is:

\Delta p=m\Delta v=750,000\cdot42=31,500,000=\fbox{$32,000,000\:\mathrm{Ns}$}(two significant figures).

Impulse is also given as \Delta p = F\Delta t, where F is the average force applied and \Delta t is change in time. Since t is given as 80\mathrm{s}, we have the following equation:

F\Delta t=\Delta p\\\\F=\frac{\Delta p}{\Delta t},\\\\F=\frac{31,500,000}{80},\\\\F=393,750=\fbox{$390,000\:\mathrm{N}$}(two significant figures).

7 0
3 years ago
How many electrons are contained on the negatively-charged side of a capacitor when it is fullycharged if it is connected to a 1
AVprozaik [17]

Answer:

Explanation:

Capacitance of the capacitor

C = ε₀ A / d

(8.85 x 10⁻¹² x .25² x 10⁻⁴) / 1 x 10⁻³

C = .553125 x 10⁻¹³ F

Charge = capacitance x volt

= .553125 x 10⁻¹³ x 1.5

= .8296875 x 10⁻¹³ C

no of electrons

= charge / charge on one electron

= .8296875 10⁻¹³/ 1.6 x 10⁻¹⁹

= 5.2 x 10^5

3 0
4 years ago
Read 2 more answers
Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
tresset_1 [31]
We are given with the data that the angle of velocity is above the negative axis. hence, the angle lies in the second quadrant with negative x axis and positive y axis. In this case, the x component is -12 cos 60 equal to -6 m/s while the y-component is 12 sin 60 equal to 6 sqrt of 3 m/s. 
6 0
3 years ago
All of the inner planets
Darina [25.2K]

Answer:

The answer to this is D two of the above

7 0
3 years ago
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