Answer:
Explanation:
consider the mass of each train car be m
m₁ = m₂ = m₃ = m
speed of the three identical train
u₁ = u₂ = u₃ = 1.8 m/s
m₄ = m u₄ = 4.5 m/s
m₅ = m u₅ = 0 (initial velocity )
final velocity
v₁ = v₂ = v₃ = v₄ = v₅ = v
using conservation of momentum
m₁u₁ + m₂u₂ + m₃u₃ + m₄u₄ + m₅u₅ = m₁v₁ + m₂v₂ + m₃v₃ + m₄v₄ + m₅v₅
m (1.8 + 1.8 + 1.8 +4.5) = 5 m v
Answer:
v = 0.33 m/s
Explanation:
The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:
<u>Where:</u>
m1: is the mass of the water skier = 62.0 kg
m2: is the mass of the boat = 775 kg
v1i: is the initial velocity of the water skier = 4.50 m/s
v1f: is the final velocity of the water skier = ?
v2i: is the initial velocity of the boat = 0
v2f: is the final velocity of the boat = ?
Since the final velocity of the skier is the same that the final velocity of the boat, we have:
Therefore, the final velocity of the skier and boat is 0.33 m/s.
I hope it helps you!