Add then divide the hint clearly backs it up two so yeahh
Based on the calculations, the average velocity is equal to 360 m/s and the percent difference is equal to 4.72%.
<h3>What is average velocity?</h3>
An average velocity can be defined as the total distance covered by a physical object divided by the total time taken.
<h3>What is an
average?</h3>
An average is also referred to as mean and it can be defined as a ratio of the sum of the total number in a data set to the frequency of the data set.
<h3>How to calculate the
average velocity?</h3>
Mathematically, the average velocity for this data set would be calculated by using this formula:
Average = [F(v)]/n
Vavg = [v₁ + v₂ + v₃ + v₄ + v₅)/5
Since the values of the average velocity from the table are missing, we would assume the following values for the purpose of an explanation:
Substituting the parameters into the formula, we have:
Vavg = [300 + 450 + 500 + 250 + 300)/5
Vavg = 1800/5
Vavg = 360 m/s.
Next, we would calculate the percent difference by using this formula:
![Percent \;difference = \frac{[V_{avg}\;-\;V_{sound}]}{V_{sound}} \times 100](https://tex.z-dn.net/?f=Percent%20%5C%3Bdifference%20%3D%20%5Cfrac%7B%5BV_%7Bavg%7D%5C%3B-%5C%3BV_%7Bsound%7D%5D%7D%7BV_%7Bsound%7D%7D%20%5Ctimes%20100)
Percent difference = [360 - 343]/360 × 100
Percent difference = 17/360 × 100
Percent difference = 0.0472 × 100
Percent difference = 4.72%.
Read more on average here: brainly.com/question/9550536
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Answer:
1.01 × 10⁵ Pa
Explanation:
At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.
We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.
Pressure at a depth is given by :

Where
is the density of air, 
So,

Total pressure, P = Atmospheric pressure + 12 Pa
= 1.013 × 10⁵ Pa + 12 Pa
= 1.01 × 10⁵ Pa
Hence, the total pressure is 1.01 × 10⁵ Pa.
Answer:
B is the best answer for the question
Answer:
b. electric potential energy.
Explanation:
The energy required to move a charge against the electric field is known as the electric potential energy. As in above case positively charged body is exerting an electric field on the positive charge. As the same charges repel so the charge tend to move away. In order to push it towards the body we need a work done. As it is hard to push the positive charged particle towards the positive electric field. So in the cases like these particle occupies the electric potential energy.