Let the width be w, length = 3w and height = 2w
Volume = length x width x height = w x 3w x 2w = 6w^3
6w^3 = 2,058
w^3 = 2,058/6 = 343
w = ∛343 = 7
width = 7 cm
-7y+3 is the answer that you are looking for
I believe B is the answer
Answer:
176/1125 or 0.156
Step-by-step explanation:
There are 15 bulbs, of which 4 are 23-watt. The probability of selecting a 23-watt bulb = 4/15. If we call this probability x, then x = 4/15.
The probability of selecting a 13-watt or 18-watt bulb is the probability of not selecting a 23-watt bulb. If we call this y, y = (6+5)/15 = 11/15. It follows that x and y are mutually exclusive. Here, we have a binomial distribution.
The number of ways of selecting exactly two 23-watt bulbs out of three is
The probability of selecting them is