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artcher [175]
3 years ago
8

An adventure park charges $16 per adult and $10 per child (6 - 16 years) to enter the park. Melissa, who is 9, and her five fami

ly members, (2 adults and 3 more children) went to the park. Melissa's dad paid with a one-hundred dollar bill. How much change did her dad get back after he paid the park entrance fees?
Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Total charge at park, T = 2×charge on adults + 4×charge on children .

T =$(2×16 + 4×10)

T = $72

Now, Melissa's father paid $100 .

Amount her father get back is :

A = $( 100 - 72 )

A = $28

Therefore, her father get $28 back.

Hence, this is the required solution.

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Answer:

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Step-by-step explanation:

x+1=0(squared).

x+1=0 (anything raise to the power 0 is 0

collect like terms =x=-1

therefore x=-1

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] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
Bad White [126]

Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

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The first one and the last one, the 2 middle ones are not corresponding

5 0
3 years ago
A jar contains 2 orange, 4 green, 2 white and 2 black balls. What is the probability of drawing an orange ball without putting i
KonstantinChe [14]

Answer:

2/45

Step-by-step explanation:

We are told that:

A jar contains 2 orange, 4 green, 2 white and 2 black balls.

The total number of balls in the jar is calculated as:

2 orange balls + 4 green balls + 2 white balls + 2 black balls = 10 balls

The probability of drawing an orange ball = P(Orange) = 2/10

The probability of drawing a black ball = P(Black) = 2/10

Therefore, the probability of drawing an orange ball without putting it back, then drawing a black ball is calculated as:

2/10 × 2/9 = 4/90

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3 years ago
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