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tino4ka555 [31]
3 years ago
14

On the basis of electronegativity, which of these pairs of elements is most likely to form polyatomic ions?

Chemistry
1 answer:
Vinvika [58]3 years ago
7 0
Correct Answer: <span>O and P

Reason: 
The nature of bond depends on the electronegativity difference of constituent atoms. If difference in electronegativity of constituent atoms is more, it will result in ionic bonding. Alternatively, if difference in electronegativity of constituent atoms is less, it will prefer covalent bonding. Further,  covalently bonded </span><span>elements are most likely to form polyatomic ions.

In present case, electronegativity difference of O and P is minimum. Hence, they </span><span>are most likely to form polyatomic ions.</span>
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Answer:

Electrons are lost during oxidation (LEO)

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Answer:

33300J

Explanation:

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Unknown:

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Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

 So;

            H  = mL

m is the mass

L is the latent heat of melting ice

  Now, insert the parameters and solve;

            H = mL

 mass from gram to kilogram;

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8 0
2 years ago
A 11.97g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how man
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<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

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  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

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A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

  • But;

% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100

  • Therefore;

Mass of the element = (% composition of an element × mass of the compound) ÷ 100

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Which statement is true?
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The correct answer is in an exothermic reaction the energy of the product is less than the energy of the reactants.

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8 0
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