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frutty [35]
3 years ago
10

The process or method , by which a magnet loses its power , is called…………………… ..

Chemistry
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

I think it is called demagnetisation.

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The melting and boiling points of quartz are very high because of the compound’s ____________________.
makvit [3.9K]

Answer:

Network Structure

Explanation:

4 0
4 years ago
Why are most anions basic in H2O? Give formulas of four anions that are not basic.
AVprozaik [17]

Answer:

The anions that can act as bases (conjugate bases of weak acids) have the capability to hydrolyse water and produce OH− ions. Cl−, Br−NO−3, SO2−4 are all conjugate bases of strong acids that don't have the capability to hydrolyse water and so they aren't basic.

Explanation:

5 0
3 years ago
During a phase change, the temperature of a substance _____.
adell [148]

Answer: remains constant.


Justification:


1) The phase changes are:


i) Boiling: pass from liquid to gas (absorbs heat energy)

ii) Condensation: pass from gas to liquid (release heat energy)

iii) Melting: pass from solid to liquid (absorb heat energy)

iv) Freezing: pass from liquid to solid (release heat energy)

v) Sublimation: pass from solid to gas (absorbs heat energy)

vii) Deposition: pass from gas to solid (release heat energy)


2) When a phase change occurs, whichever it is, the heat energy related with the process, either absortion or release, is used, to overcome the intermolecular forces (in the case of heat energy absortion) or to create stronger intermolecular forces (in the case of heat energy release).


Because of that, the heat energy exchange does not change the temperature of the substance.

8 0
3 years ago
Read 2 more answers
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0
4 years ago
2. What will you change (the independent variable) in each test?
skad [1K]

Answer:the other vaiabable

Explanation:

8 0
4 years ago
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