A 5.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26
1 answer:
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Answer:
7.5Watts
Explanation:
Given parameters:
Force of lift = 25N
Height = 3.6m
Time = 12s
Unknown:
Power output = ?
Solution:
Power is the rate at which work is done ;
Power =
Power = = 7.5Watts
Answer:False
Explanation:
The given statement is false
because the sine ratio is the ratio formed by the side opposite the acute angle to the hypotenuse
Given data:
* The extension of the steel wire is 0.3 mm.
* The length of the wire is 4 m.
* The area of cross section of wire is,
* The young modulus of the steel is,
Solution:
The young modulus of the steel in terms of the force and extension is,
where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,
Substituting the known values,
Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.