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PSYCHO15rus [73]
3 years ago
9

A 5.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26

Physics
1 answer:
devlian [24]3 years ago
6 0

Answer:

Incomplete question.

Explanation:

What do you require? is it the work done?

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The reflection of a sound wave from a wal is called
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I think its an echo?
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A hi-lo lifts an 25 N skid to top of a pallet rack. The pallet rack is 3.6 meters tall. The hi-lo takes 12 seconds to get the sk
mojhsa [17]

Answer:

7.5Watts

Explanation:

Given parameters:

Force of lift  = 25N

Height  = 3.6m

Time  = 12s

Unknown:

Power output  = ?

Solution:

Power is the rate at which work is done ;

     Power  = \frac{force x height }{time}  

   Power  = \frac{25 x 3.6}{12}    = 7.5Watts

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3 years ago
a car is moving with a constant speed of 20 meters per second.What total distance does the car travel in 2 minutes
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There are 120 seconds in two minutes, so to find the answer, you multiply 20 x 120 to get 2400 meters.
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3 years ago
The sine ratio is the ratio formed by the hypotenuse over the side opposite the acute angle. True False
Paha777 [63]

Answer:False

Explanation:

The given statement is false

because the sine ratio is the ratio formed by the side opposite the acute angle to the hypotenuse

\sin (acute\ angle)=\frac{Perpendicular}{hypotenuse}  

4 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
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