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LiRa [457]
2 years ago
5

Physics please help !!

Physics
1 answer:
jeyben [28]2 years ago
3 0

Answer:

(C)

Explanation:

Volume is independent of the mass. Volume depends on the spatial dimensions so no matter how much you change the mass, volume will remain the same.

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Why do we feel the effects of gravity given that the gravitational force is so weak?
almond37 [142]
Any two objects in the universe attract each other. Gravity is the force exerted by earth on you (you exert the same force on earth) but due to the fact that earth has a huge mass compared to yours, you will be attracted to earth only by a small gravitational force.

6 0
3 years ago
Read 2 more answers
How does the gravitational force between two objects change if the distance
Anestetic [448]

Answer:

The Gravitational Force is reduced 4 times

Explanation:

The equation of Gravitational force follows:

F = (G*m1*m2)/r^2

Assume that G*m1*m2 = 1 and r = 1:

F = 1/1^2 = 1 N

Multiply the radius by 2

F = 1/2^2 = 1/4 N

So doubling the distance reduces the force 4 times.

7 0
3 years ago
Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!!!
GrogVix [38]
I do believe that the answer is D.  

Hope this is right! Have a great day! :-)
7 0
3 years ago
Ex 1) A Major League baseball pitcher throws a baseball straight up into the air and the ball travels for 4
nlexa [21]

Answer:

52 / 4 = 13 m/s

Explanation:

7 0
3 years ago
A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.
fenix001 [56]

Question

What is the length of the pipe?

Answer:

(a) 0.52m

(b) f2=640 Hz and f3=960 Hz

(c) 352.9 Hz

Explanation:

For an open pipe,  the velocity is given by

v=\frac {2Lf}{n}

Making L the subject then

L=\frac {nV}{2f}

Where f is the frequency,  L is the length,  n is harmonic number,  v is velocity

Substituting 1 for n,  320 Hz for f and 331 m/s for v then

L=\frac {1*331}{2*320}=0.5171875\approx 0.52m

(b)

The next two harmonics is given by

f2=2fi

f3=3fi

f2=3*320=640 Hz

f3=3*320=960 Hz

Alternatively, f2=2\times \frac {v}{2L} and f3=3\times \frac {v}{2L}

f2=2\times \frac {331}{2*0.52}=636.5 Hz\\f3=3\times \frac {331}{2*0.52}=954.8 Hz

(c)

When v=367 m/s then

f1= \frac {v}{2L}\\f1= \frac {367}{2*0.52}=352.9 Hz

5 0
3 years ago
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