Answer:
0.34148 m
Explanation:
= Resistivity of tungsten = 
d = Diameter = 0.0018 inch
r = Radius = 
= Temperature coefficient of tungsten = 
Power is given by
We have the equation
![R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega](https://tex.z-dn.net/?f=R_2%3DR_1%5B1%2B%5Calpha%28T_2-T_1%29%5D%5C%5C%5CRightarrow%20R_1%3D%5Cdfrac%7BR_2%7D%7B1%2B%5Calpha%28T_2-T_1%29%7D%5C%5C%5CRightarrow%20R_1%3D%5Cdfrac%7B144%7D%7B1%2B0.0045%282550-25%29%7D%5C%5C%5CRightarrow%20R_1%3D11.64812%5C%20%5COmega)
Resistance is given by
The length of the filament is 0.34148 m
Answer: 244.05 J
Explanation:
To find speed at 30 m above the ground use equation:
V²=Vo²-2Gs
V0=31.4m/s
s=30m
G=9.81m/s²
-----------------------
V²=31.4²-2*9.81*30
V²=985.96+588.6
V²=1574.56
V=39.68m/s ---speed of arrow on 30 m obove the ground
Use equation for kinetic enrgy:
Ke=mV²/2
m=0.155kg
V=39.68m/s
-------------------------
Ke=0.155kg*(39.68m/s)²/2
Ke=0.155*1574.5/2
Ke=244.05J
Answer:
16200 km/s
270 km/min
4.5 km/h
Explanation:
Acceleration Formula: Average Acceleration = Δv/Δt (change in velocity over change in time)
Simply plug in our known variables and solve:
a = (45.0 - 0)/10
a = 45.0/10
a = 4.5 km/h
