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2 years ago

Which condition would cause the altimeter to indicate a lower altitude than actually flown (true altitude)

Physics

1 answer:

solmaris [256]2 years ago

7 0

Answer:

Explanation: When the temperature is colder than standard, you are at an altitude lower than your altimeter indicates. When the temperature is warmer than standard, you are higher than your altimeter indicates

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1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the

Juli2301 [7.4K]

The force exerted on the car during this stop is 6975N

<u>Explanation:</u>

Given-

Mass, m = 930kg

Speed, s = 56km/hr = 56 X 5/18 m/s = 15m/s

Time, t = 2s

Force, F = ?

F = m X a

F = m X s/t

F = 930 X 15/2

F = 6975N

Therefore, the force exerted on the car during this stop is 6975N

6 0

2 years ago

Which of the following lists the elements in order, from those having the least protons to those having the most protons in the

Tema [17]

Answer:

Explanation:

O has 8 protones,S tiene 16, Se 34 y Te 52.

6 0

2 years ago

Read 2 more answers

A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example?

scZoUnD [109]

This would be a negative force because they are going in different directions

4 0

3 years ago

Read 2 more answers

A technician wearing a brass bracelet enclosing area 0.00500 m2 places her hand in a solenoid whose magnetic field is 4.50 T dir

notka56 [123]

Answer:

39.375 A

Explanation:

To find the induced current, we use the relation

e = -ΔΦ/Δt, where

ΔΦ = change in magnetic flux of the bracelet

Δt = change in time, = 20 ms

Also, Φ = A.ΔB, such that

A = area of the bracelet, 0.005m²

ΔB = magnetic field strength of the bracelet = 1.35 - 4.5 = -3.15 T

ΔΦ = A.ΔB

ΔΦ = 0.005 * -3.15

ΔΦ = -.01575 wb

e = -ΔΦ/Δt

e = -0.01575 / 20*10^-3

e = 0.7875 V

From the question, the resistance of the bracelet is 0.02 ohm, so

From Ohms Law, I = V/R

I = 0.7875 / 0.02

I = 39.375 A

6 0

2 years ago

A baseball is thrown straight up. the drag force is proportional to v2. part a in terms of g, what is the y-component of the bal

steposvetlana [31]

At the position of terminal speed the net acceleration of the ball will become zero

As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.

So here at this position we can say

$F_d = F_g$

$kv^2 = mg$

$v =\sqrt{\frac{mg}{k}}$

now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be

$F_{net} = mg + F_d$

$F_{net} = mg + kv^2$

here speed of the ball is half of the terminal speed

$v = \frac{1}{2}*\sqrt{\frac{mg}{k}}$

then we have

$F_{net} = mg + k*\frac{mg}{4k}$

$F_{net} = \frac{5mg}{4}$

now acceleration will be given as

$a = \frac{F_{net}}{m}$

now we have

$a = \frac{5g}{4}$

$a = 12.25 m/s^2$ downwards

7 0

3 years ago