With u = <-7, 6> and v = <-4, 17>, we have
u + 3v = <-7, 6> + 3 <-4, 17> = <-7, 6> + <-12, 51> = <-19, 57>
We want to find a vector w such that
u + 3v + w = <1, 0>
Subtract u + 3v from both sides to get
w = <1, 0> - (u + 3v) = <1, 0> - <-19, 57>
w = <20, -57>
Answer:
squars are all parallel and equal to 90
Step-by-step explanation:
b
<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>
This is the isosceles triangle. Therefore, the angles at the base are congruent.
We know that the sum of the measures of the angles in a triangle is 180°.
Therefore we have the equation:

<em>subtract 38 from both sides</em>
<em>divide both sides by 2</em>

<h3>Answer: x = 71.</h3>