I only need help with #10 :) offering 10 pts

Mathematics

1 answer:

Semenov [28]2 years ago

8 0

Answer:

The length of one side of the square is 3.

Step-by-step explanation:

The perimeter of any given shape is all of the sides added together. So, the perimeter of the triangle is 5x + 4x + 3x. Added together, 12x.

The perimeter of the square is (x + 2)*4. Distributed, it's 4x + 8. Since we know they're equal, set it up like this:

12x = 4x + 8

You then find that x = 1. Plug that into one side of the square, x + 2, to get 3.

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I need help, please.

Usimov [2.4K]

2 rooms would be 62+42 which is 104

3 rooms would be 104+42 which is 146

4 rooms would be 146+42 which is 188

5 rooms would be 188+42 which is 230

6 rooms would be 230+42 which is 272

but these are the prices including the 20$

without the 20$ the prices would be

2 rooms is 84

3 rooms is 126

4 rooms is 168

5 rooms is 210

6 rooms is 252

4 0

2 years ago

Read 2 more answers

I got 10 but can someone make sure because I want to get a 100

Sati [7]

Answer:

i think 10

Step-by-step explanation:

6 0

2 years ago

The table below shows the budget for the Smith family.

tiny-mole [99]

Answer:

415 300 213 3400 4500 = 8415

4500 450 415 300 215 3400 = 9280

8828 times 100 divided by 9280 =9 5.1293103448

95.1 percent (simplified)

Step-by-step explanation: income is income rescieved, id.k if income taxes is given to you but taxes is usually taken away from you, college savings, retirement saving and emergency funds are income, and living expenses is for living and you use it on what ever you want. mainly food.

8 0

3 years ago

Read 2 more answers

How would I solve this Rational Equation? <br><br>Solve for all values of x.

Nesterboy [21]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.