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andrey2020 [161]
3 years ago
14

Nico Joven presently earns $348.40 per week. He claims

Mathematics
1 answer:
Anika [276]3 years ago
6 0

Answer:

tbh i be wasting m time and ur tiem no kap

Step-by-step explanation:

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A and B are postive integers such that 1/a + 1/b +1/ab = 1. Find ab
Kitty [74]

Answer: ab =6

have:

\frac{1}{a}+\frac{1}{b}+\frac{1}{ab}=1\\\\=>\frac{b}{ab}+\frac{a}{ab}+\frac{1}{ab}=1\\\\\frac{a+b+1}{ab}=1

=> a + b + 1 = ab

⇔ a + b + 1 - ab = 0

⇔ b - 1 - a(b - 1) + 2 = 0

⇔ (b - 1)(1 - a) = -2

because a and b are postive integers => (b - 1) and (1 - a) also are integers

=> (b - 1) ∈ {-1; 1; 2; -2;}

(1 -a) ∈  {-1; 1; 2; -2;}

because (b -1).(1-a) = -2 => we have the table:

b - 1        -1             1              2             -2

1 - a         2            -2            -1              1

a              -1            3             2              0

b              0            2             3              -1

a.b            0           6             6               0

because a and b  are postive integers

=> (a;b) = (3;2) or (a;b) = (2;3)

=> ab = 6

Step-by-step explanation:

4 0
3 years ago
A tool and die company buys a machine for 175,000 and it depreciates at a rate of 30% per year. Find the depreciated value of th
DaniilM [7]
1417.5 is the answer and this is a tricky question. 
8 0
3 years ago
What is 2+2 fjjfjfjfjfjfjfjffjfffjf fjfjfjjffjfjfjfjf
Sveta_85 [38]

\large\bf\orange{ \diamond} \rm \:  \:2 \:  +  \: 2 \:  =  \: 4

3 0
3 years ago
If half a kilogram of potatoes costs 0.0125$ how many kilograms could be bought for 50 cents?​
Oliga [24]

Answer:

4000 kilos

Step-by-step explanation:

on my assignment i got t right i hope it works for u

(edit) mostly be 2000 kilos but prob best answer could be 200 ill edit if its wrong

5 0
3 years ago
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
salantis [7]
The formula for the average value of a function is \frac{1}{b-a}  \int\limits^b_a {f(x)} \, dx where b is the upper bound and a is the lower.  For us, this formula will be filled in accordingly.  \frac{1}{2}  \int\limits^2_0 {(2x^2+3)} \, dx.  We will integrate that now: \frac{1}{2}[ \frac{2x^3}{3}+3x] from 0 to 2.  Filling in our upper and lower bounds we have \frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0] which simplifies to \frac{1}{2}( \frac{16}{3}+6) and \frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3}) which is 17/3 or 5.667
7 0
3 years ago
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