Answer:
Phenotype- 100% for the recessive trait (aa, bb)
Explanation:
This happens because of the mode of inheritance, which would mask the dominant trait, during a cross. Therefore, this would lead to all offspring not expressing the dominant phenotype
Answer:
In a fruit fly experiment, grey body, normal winged (homozygous dominant) fruit flies were mated with black body, short winged (homozygous recessive) fruit flies. The F1 dihybrid females were then used in a test cross. If the genes are always linked and no crossing over occurs, what would be the predicted ratio in the F2 generation?
GG x bb = Gb, Gb, Gb and Gb F1 generation
grey body heterozygous offspring 4:0
Gb x Gb= GG, Gb, Gb, and bb F2 generation
3:1 three grey body fly and one black body fly
Explanation:
Answer:
Reaction 1
Explanation:
Reaction 1 would be the most suitable in this case. This is so because in reference to the question you are wanting to keep the food warm over long periods. So in reference to the data in the chart reaction 1 continues to heat up over long periods of time. However, with the other reactions (2, 3, 4) temperatures vary and some even decrease constantly. Therefore showing that the other reactions are invalid to help reach your goal referencing back to the question.
Answer:
A living organism's position in the flow of energy through an ecosystem.
The rough endoplasmic reticulum also known as RER is covered in ribosomes and helps produce most of the proteins. Smooth endoplasmic reticulum also known as SER does not have these ribosomes, and it is almost solely for producing lipids.
Good luck :)
