The electric field between two plates is 40 V/m.
To find the electric field between two plates, the values are given are,
distance = 3 cm
Voltage v = 120 v
<h3>What is electric field between two plates?</h3>
The electric field between plates is the area where the charges between two plates, influences can be seen. For example, if a charged particle is placed near any charged plate, the plate exerts an electric force to attract or repel the charged particle.
Formula is given as,
E = V / d (v/m)
Substituting the given values,
= 120 /3
=40 v/m
Hence, the answer is 40 v/m.
Learn more about electric field,
brainly.com/question/8971780
Radio waves have longer wavelengths and lower frequencies than microwaves.
infrared is longer wavelengths and lower frequencies than UV light
The answer is <span>higher than.
</span><span>A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency higher than that actually being produced by the object.
Why?
</span>As the source of the waves is moving toward the observer, each of the successive wave crest<span> is emitted from a position closer to the observer than the previous wave.
Thus each wave takes slightly less time to reach the observer than the previous wave. So, the time between the arrival of successive wave crests at the observer is reduced, increasing the frequency. </span>
Answer:
His kinetic energy increases, potential energy decreases
The sum of kinetic and potential energy is a constant at any instant before he comes to rest.
Explanation:
Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression
, so as he moves his kinetic energy increases.
When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.
Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.
mgh+
= Constant
Answer:
The height of the image of the candle is 20 cm.
Explanation:
Given that,
Size of the candle, h = 12 cm
Object distance from the candle, u = -6 cm
Focal length of converging lens, f = 15 cm
To find,
The height of the image of the candle.
Solution,
Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

v is image distance

If h' is the height of the image. Magnification is given by :


So, the height of the image of the candle is 20 cm.