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cricket20 [7]
2 years ago
12

Mr Bissell creates a diagram of electric and magnetic fields to teach his students about the concepts. He includes the similarit

ies and differences
between the fields on the diagram Which of the following statements should he add about the similanties between the two fields?
Physics
1 answer:
tamaranim1 [39]2 years ago
3 0

The similarity between electric field and magnetic field is that both fields attract or repel charges in the field.

<h3>What is electric field?</h3>

An electric field is a region of space that surrounds electrically charged particles and exerts force on other charged particles within the filed.

<h3>What is magnetic field?</h3>

A magnetic field is a vector field that describes the magnetic influence on moving electric charges.

<h3>Similarity between electric field and magnetic field</h3>

The similarity between electric field and magnetic field is that both fields attract or repel charges in the field.

Learn more about electric and magnetic field here: brainly.com/question/1594186

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The voltage between two parallel plates separated by a distance of 3.0 cm is 120 v. the electric field between the plates is:___
soldier1979 [14.2K]

The electric field between two plates is 40 V/m.

To find the electric field between two plates, the values are given are,

distance =  3 cm

Voltage v = 120 v

<h3>What is electric field between two plates?</h3>

           The electric field between plates is the area where the charges between two plates, influences can be seen. For example, if a charged particle is placed near any charged plate, the plate exerts an electric force to attract or repel the charged particle.

Formula is given as,

                        E = V / d (v/m)

Substituting the given values,

                           = 120 /3

                           =40 v/m

Hence, the answer is 40 v/m.

Learn more about electric field,

brainly.com/question/8971780

4 0
2 years ago
PLEASE HELP TIMED
Igoryamba

Radio waves have longer wavelengths and lower frequencies than microwaves.

infrared is longer wavelengths and lower frequencies than UV light

5 0
3 years ago
Read 2 more answers
A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency ___ that actually bein
Readme [11.4K]
The answer is <span>higher than.
</span><span>A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency higher than that actually being produced by the object.

Why?
</span>As the source of the waves is moving toward the observer, each of the successive wave crest<span> is emitted from a position closer to the observer than the previous wave.
Thus each wave takes slightly less time to reach the observer than the previous wave. So, the time between the arrival of successive wave crests at the observer is reduced, increasing the frequency. </span>
5 0
4 years ago
Read 2 more answers
-What can you say about the snowboarder’s kinetic energy as he moves?
Damm [24]

Answer:

  His kinetic energy increases, potential energy decreases

  The sum of kinetic and potential energy is a constant at any instant before he comes to rest.

Explanation:

  Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression \frac{1}{2} mv^2, so as he moves his kinetic energy increases.

  When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.

  Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.

                             mgh+\frac{1}{2} mv^2= Constant

 

7 0
4 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
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