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3 years ago

How would I solve this question?

Mathematics

2 answers:

Leona [35]3 years ago

7 0

Jaid is correct i agree with that peson

morpeh [17]3 years ago

6 0

The equasion is y= -1x=6 because it's subtractio one each time and the 0 figure is 6.

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A bag contains 3 teal balls and 2 magenta balls. Blake picks one ball, replaces it, and then picks another ball. What is the pro

lawyer [7]

3/10

Plz give brainliest

3 0

3 years ago

point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form

IRISSAK [1]

Answer:

$4\sqrt{10}$

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of point A and point B in distance formula we will get,

$\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}$

$\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}$

$\text{Distance between point A and point B}=\sqrt{16+144}$

$\text{Distance between point A and point B}=\sqrt{160}$

$\text{Distance between point A and point B}=4\sqrt{10}$

Therefore, the length of segment AB is $4\sqrt{10}$ .

3 0

3 years ago

−3t≥39 What is the answer

Daniel [21]

Answer:

-3t ≥39

-3t/-3 ≥39/-3

t≤-13

3 0

2 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$