hey there!
atomic mass cobalt = 58.9332 amu
therefore:
1 mol Co ------------ 58.9332 g
moles ------------ 50 g
moles = 50 x 1 / 58.9332
moles = 50 / 58.9332
= 0.8484 moles of Co
Hope this helps!
Answer: CO is a limiting reagent with regards to the Fe production.
Explanation:

Moles of CO = 
moles of 
According to reaction , 3 mole of CO reacts with 1 mole of
then , 0.4714 moles of CO will react with :
moles of
that is 0.1571 moles.
0.4714 moles of CO will react with 0.1571 moles of
which means that CO is present in limited amount acting as limiting reagent.
Mole remaining of
= 0.2673 mol - 0.1571 mol = 0.1102 mol
Hence, CO is a limiting reagent and
is an excessive reagent.
Balance the equation first:
2 Fe+6 HNO3→2 Fe(NO3)3+3H2
Then calculate mass of Iron :
4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe
Now use Stoichiometry:
371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3
Convert moles of nitric acid to grams
19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3
Answer:
b: Neither atoms will have a full valence shell
Explanation:
I think sooo