Question

4. What is the molar concentration and grams/Liter of a NaOH solution if 86 ml are titrated to an

Answer 1

Answer:

0.76 M

30 g/L

Explanation:

Step 1: Given data

• Molarity of the acid (Ma): 0.175 M

• Volume of the acid (Va): 375 mL

• Molarity of the base (Mb): ?

• Volume of the base (Vb): 86 mL

Step 2: Calculate the molarity of the base

We will use the following expression.

$Ma \times Va = Mb \times Vb\\Mb = \frac{Ma \times Va}{Vb} = \frac{0.175M \times 375mL}{86mL} = 0.76 M$

Step 3: Calculate the concentration of the base in g/L

The molar mass of NaOH is 40.00 g/mol.

$\frac{0.76mol}{L} \times \frac{40.00g}{mol} = 30 g/L$