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jonny [76]
3 years ago
6

Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 12.0 mol of al und

ergoes the reaction with a stoichiometrically equivalent amount of fe2o3.
Chemistry
1 answer:
V125BC [204]3 years ago
5 0
Answer : 5100 KJ

Explanation :
In the given reaction of 

Fe_{2} O_{3} + 2Al ----\ \textgreater \  Al_{2}O_{3} + 2Fe

we can see that 2 moles of Al is producing -850 KJ of energy

so for 12 moles of Al we can calculate as;

12 moles of Al X\frac{-850}{2 moles of Al} = -5100 KJ

So, we can say that 12 moles of Al will need -5100 KJ of energy.
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