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Alekssandra [29.7K]
3 years ago
11

Write each relation in standard form and then find the y-intercept for each relation:

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

In standard form, the relation is y = 5x^2 + 100x + 507

The y-intercept is y = 507.

Step-by-step explanation:

Quadratic equation:

In standard form, it is written as:

y = ax^2 + bx + c

The y-intercept is c.

a) y = 5(x+10)^2 +7

We open the binomial to write in standard form. So

y = 5(x + 10)^2 + 7

y = 5(x^2 + 20x + 100) + 7

y = 5x^2 + 100x + 500 + 7

y = 5x^2 + 100x + 507

In standard form, the relation is y = 5x^2 + 100x + 507

The independent term, c, is 507, so the y-intercept is y = 507.

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write a quadratic function in vertex form whose graph has the vertex (1,0) and passes through point (2,-17)
kobusy [5.1K]

Answer:

\displaystyle f(x) = -17(x-1)^2

Step-by-step explanation:

We want to write a quadratic function in vertex form whose vertex is (1, 0) and passes through the point (2, -17).

Recall that vertex form is given by:

\displaystyle f(x) = a(x-h)^2 + k

Where (<em>h</em>, <em>k</em>) is the vertex and <em>a</em> is the leading coefficient.

Since our vertex is at (1, 0), <em>h</em> = 1 and <em>k</em> = 0:

\displaystyle f(x) = a(x-1)^2

It passes through the point (2, -17). Hence, when <em>x</em> = 2, <em>y</em> = -17:

\displaystyle (-17) = a((2)-1)^2

Solve for <em>a: </em>

<em />\displaystyle a = -17<em />

<em />

In conclusion, our quadratic function in vertex form is:

\displaystyle f(x) = -17(x-1)^2

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