Question

Write each relation in standard form and then find the y-intercept for each relation:

Answer 1

Answer:

In standard form, the relation is $y = 5x^2 + 100x + 507$

The y-intercept is y = 507.

Step-by-step explanation:

Quadratic equation:

In standard form, it is written as:

$y = ax^2 + bx + c$

The y-intercept is c.

a) y = 5(x+10)^2 +7

We open the binomial to write in standard form. So

$y = 5(x + 10)^2 + 7$

$y = 5(x^2 + 20x + 100) + 7$

$y = 5x^2 + 100x + 500 + 7$

$y = 5x^2 + 100x + 507$

In standard form, the relation is $y = 5x^2 + 100x + 507$

The independent term, c, is 507, so the y-intercept is y = 507.