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4 years ago

How do you know which number is larger or smaller 572 and 321

Mathematics

2 answers:

olga_2 [115]4 years ago

7 0

Use the 100's place, wich number is bigger at the end? 5 or 2?

IgorC [24]4 years ago

7 0

First, you can look at the first digits in both numbers, which one is bigger 5 or 3? If both digits are the same, you continue this process until you find a number that is bigger than the other. (Your answer is 572)

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A starting lineup in basketball consists of two guards, two forwards, and a center.

trasher [3.6K]

Answer:

a. 390 ways

b. 0.82

Explanation

Given

Number of guard = 2

Forward = 2

Center = 1

The college team has on its roster 3 centers, 4 guards, 5 forwards, and one individual (X)

Considering the lineups without X, then lineups with X as guard, then lineups with X as forward.

Note that order doesn't matter

Calculating the lineup without player X:

Selection of 1 Center from 3 center = 3C1 = 3

Selection of 2 forwards from 5 forwards = 5C2 = 10

And

Selection of 2 guards from 4 = 4C2 = 6

Total = 6 * 10 * 3 = 180

X as a guard: (only one player is needed since X has already been selected)

Selection of 1 Center from 3 center = 3C1 = 3

Selection of 2 forwards from 5 forwards = 5C2 = 10

And

Selection of 1 guards from 4 = 4C1= 4

Total = 4 * 10 * 3 = 120

X as a forward: (only one player is needed since X has already been selected)

Selection of 1 Center from 3 center = 3C1 = 3

Selection of 1 forwards from 5 forwards = 5C1 = 5

And

Selection of 2 guards from 4 = 4C2= 6

Total = 6 * 5 * 3 = 90

Total Selection = 90 + 120 + 180 = 390 ways

Considering that player X and Y sit out, player X play while Y sits out, player Y plays while X sits out and player X and Y play (either as a guard, forward or split duties).

Calculating the lineup without player X and Y

Selection of 1 Center from 4 center = 4C1 = 4

Selection of 2 forwards from 4 forwards = 4C2 = 6

And

Selection of 2 guards from 4 = 4C2 = 6

Total = 4 * 6 * 6 = 144

Calculating the lineup without player X but not Y

X as a forward: (only one player is needed since X has already been selected)

If X plays as forward

Selection of 1 Center from 4 center = 4C1 = 4

X plays as forward = 4C1 = 4

And

Selection of 2 guards from 4 = 4C2= 6

Total = 4 * 4 * 6 = 96

If X plays as guard

Selection of 1 Center from 4 = 4C1 = 4

Selection of 2 forwards from 4 = 4C2 = 6

And

X as guard = 4C1= 4

Total = 4 * 6 * 4 = 96

So, if X play and Y sits out; total = 96 + 96 = 192

It's same if Y plays and X sits out = 192

Considering that both X and Y plays

As guards

Selection of 1 Center from 4 = 4C1 = 4

Selection of 2 forward from 4 = 4C2 = 6

And

X and Y as guard = 4C0 = 1

Total = 4 * 6 * 1 = 24

As forwards

Selection of 1 Center from 4 = 4C1 = 4

Selection of 2 guards from 4 = 4C2 = 6

And

X and Y as forward = 4C0 = 1

Total = 4 * 6 * 1 = 24

Both on split duties

Selection of 1 Center from 4 = 4C1 = 4

Selection of1 from 4 forward= 4C1 = 4

And

One from 4 forward = 4C1= 4

Total = 4 * 4 * 4 = 72

Total = 72 +24 + 24 = 120

Total Required Selection = 144+192+192+120 = 648

Overall Possible Selection = 12C5 = 792

Probability = 648/792 = 0.82 ----- Approximated

6 0

4 years ago

Putting the equations in slope-intercept form changes the system from

myrzilka [38]

$15x+9y=36 \rightarrow y=-\frac{5}{3}x+4 \\ \\ 10x + 6y = 36 \rightarrow y=-\frac{5}{3}x+6$

The lines are parallel.

The slopes are equal.

<h2>Explanation:</h2>

The standard form of the equation of a line is given by the form:

$Ax+By=C \\ \\ \\ Where: \\ \\ A \ is \ a \ positive \ integer \\ \\ B,C \ are \ integers$

On the other hand, the slope-intercept form of the equation of a line is given by the form:

$y=mx+b \\ \\ \\ m:Slope \\ \\ b:y-intercept$

So let's convert each equation from the standard form to the slope-intercept form:

So, for the first equation:

$15x+9y=36 \\ \\ Solving \ for \ y: \\ \\ 9y=-15x+36 \\ \\ y=\frac{-15x+36}{9} \\ \\ y=-\frac{5}{3}x+4$

So, for the second equation:

$10x + 6y = 36 \\ \\ Solving \ for \ y: \\ \\ 6y=-10x+36 \\ \\ y=\frac{-10x+36}{6} \\ \\ y=-\frac{5}{3}x+6$

As you can see both equations have the same slope but different y-intercepts meaning that they are parallel. So these are the correct options:

The lines are parallel.

The slopes are equal.

<h2>Learn more:</h2>

Graph linear equations: brainly.com/question/13799715

#LearnWithBrainly

6 0

3 years ago

Read 2 more answers

Please provide explanation + answer :((((( im crying

Vladimir79 [104]

Answer:

1. Given

2. Subtraction property of Equality

3. Division property of Equality

I hope I helped you^_^

6 0

3 years ago

Question 1 of 25

serg [7]

Answer: wooo

Step-by-step explanation:m

8 0

3 years ago

As John walks 16 ft towards a chimney, the angle of elevation from his eye to the top of the chimney changes from 30° to 45°. Id

levacccp [35]

ANSWER

The height is $22ft$

EXPLANATION

Let the height of the chimney be x.

$\tan(45 \degree) = \frac{x}{y}$

$1 = \frac{x}{y}$

$x = y$

$\tan(30 \degree) = \frac{x}{16+ y}$

$\frac{ \sqrt{3} }{3} = \frac{x}{16 + y}$

Cross multiply

$\sqrt{3} (16 + y) = 3x$

$16 \sqrt{3} + y \sqrt{3} = 3x$

Put

$y = x$

into the equation;

$16 \sqrt{3} + x \sqrt{3} = 3x$

Group similar terms:

$16 \sqrt{3}= 3x - x \sqrt{3}$

$16 \sqrt{3}= (3 - \sqrt{3})x$

$\frac{16 \sqrt{3} }{3 - \sqrt{3} } = x$

$x=21.856$

The height of the chimney to the nearest feet is 22

6 0

3 years ago