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Lady bird [3.3K]
4 years ago
6

8. Differentiate between each of these land designations made during the Progressive Era:

Physics
1 answer:
aliya0001 [1]4 years ago
7 0

Answer:djhssnjsksksmksjsbhddbd

Explanation:

Hsjdbdkxlziucychcjxnsbsb

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A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing l
prisoha [69]

Answer:

K.E = 0.1905 J

Explanation:

From the question we are told that:

Length L=1.4m

Mass m=180g

Angular Velocity \omega=1.80rads/s

Generally the equation for Kinetic energy K.E is mathematically given by

 K.E =0.5 (1/3 ML^2 )w^2

 K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2

 K.E = 0.1905 J

5 0
3 years ago
A coil with a magnetic moment of 1.50 A-m^2 is oriented initially with its magnetic moment antiparallel? to a uniform magnetic f
svp [43]
 <span>∆U = μB = (1.5)(0.815) = 1.2225 joules</span>
6 0
3 years ago
Frank’s automobile engine runs at 100∘C. One day, when the outside temperature is 15∘C, he turns off the ignition and notes that
lapo4ka [179]

Answer:

the engine cool to 40^{o}C at 14.07 minutes

Explanation:

Given information

T(5) = 70^{o}C

T_{0} = 100^{o}C

C = 15^{o}C

Newton's law of cooling :

T(t) = C + (T_{0} - C) e^{-kt}

where

T(t) = temperature at any given time

C = surrounding temperature

T_{0} = initial temperature of heated object

k = cooling constant

to find the the time when the engine will be cooled down to 40^{o}C, we first need to find the cooling constant, k

when t = 5, T(5) = 70^{o}C

so,

T(t) = C + (T_{0} - C) e^{-kt}

T(5) = 15 + (100 - 15) e^{-5k}

70 = 15 + (85) e^{-5k}

e^{-5k} = (70 - 15) / 85

-5k = ln (55/85)

k = - ln (55/85) / 5

k = 0.087

thus, we have the eqaution

T(t) = 15 + (85) e^{-0.087t}

now we can determine the time when T(t) = 40^{o}C

40 = 15 + (85) e^{-0.087t}

e^{-0.087t} = (40-15)/85

-0.0087t = ln (25/85)

t = - ln (25/85)/0.087

t = 14.07 minutes

8 0
3 years ago
How many moles are there in 321g of silver hydroxide?
lesya [120]

Answer:

2.5705594546378 mol

Explanation:

Used this calculator

http://www.endmemo.com/chem/mmass.php

3 0
3 years ago
A two-dimensional object placed in the xy-plane has three forces acting on it: a force of 3.0 n along the x-axis acting at a poi
Anastasy [175]

the net torque about the point (-1 m, 1 m) is 4 N-m.

The resultant force acting on the object is calculated as

R^2=(-5+3)^2+2^2=2.82 N

Distance of the point from the resultant force

d^2=(-1)^2+1^2=1.414

The net torque acting on the point (-1 m, 1 m) is

T=2.82×1.41=3.98 N-m

3 0
4 years ago
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