Answer:
F = 1.06N
Explanation:
In order to calculate the force that produces the given pressure you take into account the following formula:
(1)
P: pressure = 6.0kPa = 6.0*10³ Pa
F: force = ?
A: cross-sectional area of the tube = π r^2
r: radius of the tube = 1.5cm/2 = 0.75cm = 0.75*10^-2 m
You solve the equation (1) for F, and replace the values for the area A and the pressure P:

The force tha produces a pressure of 6.0kPa in a tube with a diameters of 1.5cm is 1.06N
Answer:
a2 = 3a1
Explanation:
Detailed explanation and calculation is shown in the image below
Displacement is d
Vf² = Vi² + 2 g d
(-20²) = (+10²) + 2 (-9.8) d
-19.6 d = 300
d = -15.3 m
negative means lower
time is t
d = Vi t + 1/2 g t²
-15.3 = 10 t + (-4.9) t²
4.9 t² - 10 t -15.3 = 0
t = 3.06 s
Answer:F(of gravity) = MA
F(normal force) = MA * cos(angle)
F = 72 * 9.81 * cos28
Don't have a calculator, so can't really do all the math right there. So just plug that in
Explanation:
i dont really know