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Trava [24]
3 years ago
13

A truck travels to and from a stone quarry that is located 2.5 km to the east. What is the total distance traveled by the truck?

.00025____________________ What is its displacement? .00025
Physics
1 answer:
scoray [572]3 years ago
5 0

Answer:

5 km

0

Explanation:

The question says the truck travelled to and fro from the stone quarry.

When going to the stone quarry, the distance was 2.5 km to the east.

On returning, the distance back is also 2.5km

Therefore total distance travelled is 2.5km + 2.5km

= 5km

The displacement 8s dependent on what is the initial and also the final position. The initial and the final position are one and the same thing. Because the truck starts and goes back to the same position, the displacement is zero.

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Light of wavelength 550nm in air is found to travel at 1.96
Sedaia [141]

Answer:

ν = 5.45 x 10¹⁴ Hz

Explanation:

given,

wavelength of light = 550 nm

                                = 550 x 10⁻⁹ m

speed of light = 1.96 x 10⁸ m/s

speed of sound = 3 x 10⁸ m/s

frequency of the light = ?

we know.

v = \nu \lambda

frequency of the light in the liquid is same as the frequency of the light in the air.

 ν is the frequency of light

\nu = \dfrac{v}{\lambda}

\nu = \dfrac{3\times 10^{8}}{550\times 10^{-9}}

    ν = 5.45 x 10¹⁴ Hz

Hence, the frequency of light in the liquid is equal to ν = 5.45 x 10¹⁴ Hz

8 0
4 years ago
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
ziro4ka [17]

Answer:

(a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

Explanation:

Given that,

Rotation = 20.0 times

Time = 5.00 sec

We need to calculate the angular frequency

Using formula of angular frequency

\omega_{i}=20\times\dfrac{2\pi}{T}

put the value into the formula

\omega_{i}=20\times\dfrac{2\pi}{5.00}

\omega_{i}=8.00\pi

We need to calculate the angular displacement

Using formula of  angular displacement

\theta=6\times2\pi=12\pi

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}^2-\omega_{i}^2=2\alpha\times\theta

0-64\pi^2=2\times12\pi\times\alpha

\alpha=-\dfrac{64\pi^2}{24\pi}

\alpha=-8.3\ rad/s^2

Negative sign shows the opposite direction of the motion.

The acceleration is 8.3 rad/s².

We need to calculate the time

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha\times t

0-8\pi=-8.3t

t=\dfrac{8\pi}{8.3}

t=3.0\ sec

The time is 3.0 sec.

Hence, (a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

4 0
3 years ago
It takes a car 1.75 h to go from mile marker 10 to mile marker 115. What is the average speed of the car? Someone who took this
givi [52]

The distance from mile-mark 10 to mile-mark 115 is (115-10) = 105 miles.

Speed = (distance covered) / (time to cover the distance) .

Speed = (105 miles) / (1.75 hours)

Speed = (105/1.75) (mi/hr)

<em>Speed = 60 mph</em>  (B)

3 0
4 years ago
Read 2 more answers
Which of the following summarizes cellular respiration?
3241004551 [841]

The statement which summarizes cellular respiration is Oxygen reacts with glucose to produce carbon dioxide and water, and release energy.

<h3>What is cellular respiration?</h3>

Cellular respiration is the process by which food, in the form of glucose is transformed into energy within cells.

The food is prepared by the plants by the process of photosynthesis in presence of sunlight. This food is in the form of glucose.

The respiration of plants is done by breaking of glucose by absorbing oxygen. This produces  carbon- di- oxide and water along with the release of energy.

Thus, the cellular respiration is oxygen reacts with glucose to produce carbon dioxide and water, and release energy.

Learn more about cellular respiration.

brainly.com/question/13721588

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6 0
3 years ago
Water flows along a streamline down a river of constant width. Over a short distance, the water slows from speed v to v/3. Which
kvasek [131]

Answer:

a. It became deeper by a factor of 3.

Explanation:

What we have is water flowing down a river with constant width. The water slows from speed v to v3 over a shirt distance

Using the equation of continuity

A1V1 = A2V2 ----1

A1 is the area of rectangle

V1 is the velocity of water

Area of rectangle = length x width

We rewrite equation 1 as

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We have w1 = w2

λ1v1 = λ2v2

λ1*v1 = λ2*v/3

λ1 = λ2/3

So it becomes deeper by a factor of 3

8 0
3 years ago
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