3 years ago

3. Twelve coworkers go out for lunch together and order three pizzas. Each

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

8 0

2 slices for each person

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X^3-2x^2+5x-10=0<br> how do you solve or factor this polynomial?

pshichka [43]

$\bf x^3-2x^2+5x-10=0\implies \stackrel{\textit{doing some grouping}}{(x^3-2x^2)+(5x-10)}=0 \\\\\\ \stackrel{\textit{common factoring}}{x^2\underline{(x-2)}+5\underline{(x-2)}}=0\implies \stackrel{\textit{more common factoring}}{\underline{(x-2)}(x^2+5)}=0 \\\\[-0.35em] ~\dotfill\\\\ x-2=0\implies x=2~~~~\textit{\large\checkmark} \\\\[-0.35em] ~\dotfill\\\\ x^2+5=0\implies x^2=-5\implies x=\sqrt{-5}\implies x=i\sqrt{5}\quad \bigotimes$

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I think it’s 16 because 1/3=3/9 of hardcover books
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4 years ago

For what value of the variable will<br> b<br> the value of 3−5c be 1 less than the value of 1−c?

Crank

Answer:

c = 3/4

Step-by-step explanation:

Lets set up an equation.

You can get

3-5c + 1 = 1-c to show that it is one less.

now we can solve it.

So by combining like terms, we get:

4-5c = 1-c

that then becomes:

3-5c = -c

--> 3 = 4c

--> c = 3/4

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Step-by-step explanation:

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