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Phoenix [80]
3 years ago
13

3. Twelve coworkers go out for lunch together and order three pizzas. Each

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0
2 slices for each person
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The rectangle below has sides measuring 6cm and 5 cm. What is the area of this rectangle<br>​
sleet_krkn [62]

Answer:30 cm

Step-by-step explanation:

Area is found by two side lengths multiplied together, the two side lengths in the problem are 5cm and 6cm, 5 times 6 is 30, (plus add the measurement) which is 30 cm. :))

4 0
3 years ago
Which proportion can you use to find the value of a?
Ugo [173]

<u>Given</u>:

The given triangle is a similar triangle.

The length of the hypotenuse is 18 units.

The length of the leg is a.

The length of the part of the hypotenuse is 16 units.

We need to determine the proportion used to find the value of a.

<u>Proportion to find the value of a:</u>

We shall find the proportion to determine the value of a using the geometric mean leg rule.

Applying the leg rule, we have;

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

Substituting the values of hypotenuse, leg and part, we get;

\frac{18}{a}=\frac{a}{16}

Thus, the proportion used to find the value of a is \frac{18}{a}=\frac{a}{16}

Hence, Option D is the correct answer.

6 0
3 years ago
Whats the commisson of 660 in 10%
Sholpan [36]

Answer:

0,10×660=66

660-66= 594

6 0
3 years ago
What is the Factor 4m^3-32n^3
Klio2033 [76]

Answer:

2(47m^3-16n^3)

Step-by-step explanation:

7 0
3 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
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