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kondor19780726 [428]
3 years ago
13

A chemist dissolves silver nitrate (AgNO₃) in water. He also dissolves ammonium chloride (NH₄Cl) in water. He mixes the two solu

tions. A precipitate of silver chloride (AgCl) forms. Which chemical equation correctly represents this reaction?a. AgNO_3(s) + NH_4Cl(s) \rightarrow AgCl(s) + NH_4NO_3(s) \\b. AgNO_3(aq) + NH_4Cl(aq) \rightarrow AgCl(aq) + NH_4NO_3(aq) \\c. AgNO_3(aq) + NH_4Cl(aq) \rightarrow  AgCl(s) + NH_4NO_3(aq)
Chemistry
1 answer:
Leviafan [203]3 years ago
8 0

Answer: AgNO_3(aq)+NH_4Cl(aq)\rightarrow AgCl(s)+NH_4NO_3(aq)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equation for reaction of silver nitrate in water.and ammonium chloride in water to give precipitate of silver chloride :

AgNO_3(aq)+NH_4Cl(aq)\rightarrow AgCl(s)+NH_4NO_3(aq)

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a balloon is filled with 3.60 L of H2 gas at STP. If the balloon is taken into the sea where the pressure is 2.50 atm and the te
kherson [118]

The new volume of the hydrogen gas in the balloon is 1.5 L.

<u>Explanation:</u>

At STP, Temperature, T1 is 0° C = 0 + 273 K = 273 K

Pressure, P1 = 1 atm

Here given volume, V1 = 3.60 L

Balloon at sea,

Pressure, P2 = 2.5 atm

Temperature, T2 = 10° C = 10 + 273 = 283 K

Volume, V2 = ?

Here, we have to use the equation,

$\frac{P1V1}{T1} = \frac{P2V2}{T2}

We have to rearrange the equation to get V2 as,

$V2 = \frac{P1V1T2}{T1P2}

Now plugin the values as,

V2 = $\frac{1 atm \times 3.6 L \times 283 K}{273 K \times 2.5}

   = 1.5 L

So the new volume of the hydrogen gas is 1.5 L.

7 0
4 years ago
Read 2 more answers
What is the hybridization of the central atom in each of the following? 1. Beryllium chloride 2. Nitrogen dioxide 3. Carbon tetr
Lina20 [59]

Answer :

(1) The hybridization of central atom beryllium in BeCl_2  is, sp

(2) The hybridization of central atom nitrogen in NO_2  is, sp^2

(3) The hybridization of central atom carbon in CCl_4  is, sp^3

(4) The hybridization of central atom xenon in XeF_4  is, sp^3d^2

Explanation :

Formula used  :

\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the following molecules.

(1) The given molecule is, BeCl_2

\text{Number of electrons}=\frac{1}{2}\times [2+2]=2

The number of electron pair are 2 that means the hybridization will be sp and the electronic geometry of the molecule will be linear.

(2) The given molecule is, NO_2

\text{Number of electrons}=\frac{1}{2}\times [4]=2

If the sum of the number of sigma bonds, lone pair of electrons and odd electrons present is equal to three then the hybridization will be, sp^2.

In nitrogen dioxide, there are two sigma bonds and one lone electron pair. So, the hybridization will be, sp^2.

(3) The given molecule is, CCl_4

\text{Number of electrons}=\frac{1}{2}\times [4+4]=4

The number of electron pair are 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

(4) The given molecule is, XeF_4

\text{Number of electrons}=\frac{1}{2}\times [8+4]=6

Bond pair electrons = 4

Lone pair electrons = 6 - 4 = 2

The number of electrons are 6 that means the hybridization will be sp^3d^2 and the electronic geometry of the molecule will be octahedral.

But as there are four atoms around the central xenon atom, the fifth and sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square planar.

3 0
3 years ago
Liquid octane (CH) has a density of 0.7025 g/mL at 20 °C. Find the true mass (murue) of octane when the mass weighed in 18 air i
Goshia [24]

Explanation:

According to Buoyance equation,

          m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]

where,      m = true mass

                 m' = mass read from the balance = 17.320 g

              d_{a} = density of air = 0.0012 g/ml

              d_{w} = density of the balance = 7.5 g/ml

                    d = density of liquid octane = 0.7025 g/ml

Now, putting all the given values into the above formula and calculate the true mass as follows.

      m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]    

          = [17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}]

          = 17.320 g \times 0.999850                

          = 17.317 g

Thus, we can conclude that the true mass of octane is 17.317 g.

7 0
3 years ago
You work in a museum that has a huge, beautiful stamed-glass window: Each gamell dints the light a different coice. Recenty up a
borishaifa [10]

The plant that should be moved here to protect from malnourishment is plant 3. The correct option is C.

<h3>What is visible spectrum?</h3>

The visible light spectrum is the portion of the electromagnetic spectrum that can be seen by the human eye. Simply put, this range of wavelengths is known as visible light.

The visible spectrum, also known as the optical spectrum, is the portion of the electromagnetic spectrum whose radiation consists of photons capable of sensitizing a normal person's human eye. The corresponding visible light radiation range is identified.

That being said, plant 3 is situated in front of a green stained glass window.

Plants have chlorophyll pigment that reflects back green light, making green light less effective for photosynthesis and causing them to die as quickly as if they were kept in the dark.

Thus, the correct option is C.

For more details regarding visible spectrum, visit:

brainly.com/question/12807557

#SPJ1

3 0
1 year ago
What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20c.)?
castortr0y [4]
 <span>68g since 34/100 is 34 right? 
so if you have 200g of H2O you can put in twice as much KCl 
so it is 68g</span>
4 0
3 years ago
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