Correct If not right, but, In low temperatures intermolecular forces also increase, since molecules move more slowly, similar to what would occur in a liquid state. Just remember that ideal gas behavior is most closely approximated in conditions that favor gas formation in the first place—heat and low pressure. me.
Answer:
No oxygen
Explanation:
when something is covered in a blanket it prevents the fire from being able to have any oxygen
Answer:
How many amino acids differ between the monkey and the human sequences?
-8
Explanation:
Acids: break down in water to shape H+ particles.
Bases: break down in water to shape OH-particles.
Lets investigate acids - A solid corrosive (HCl) versus a powerless corrosive (CH3COOH).
A solid corrosive will completely separate in water to frame H+ particles.
HCl + H2O - > H3O+ + Cl-
This response is non-reversible. After disintegration, just an exact moment grouping of HCl itself stays in the arrangement, as a large portion of the weakened HCl has broken up into particles.
Ka = [H+] [Cl-]/[HCl]
A powerless corrosive, however experiences a reversible response as it just mostly separates.
CH3COOH + H2O < - > CH3COO-+ H3O+
Ka = [CH3COO-] [H3O+]/[CH3COOH]
As Ka is a steady, as more CH3COOH is included, by Le Chatelier's Principle, in this reversible response, the framework will mean to move the balance in that capacity to invert the change. Hence, less CH3COOH than included will separate into its constituent particles.
The favourability of a response (regardless of whether forward or turn around) will depend to a great extent on the temperature and change in entropy.
The same connected for bases. The main contrast is that the base separates to frame OH-particles.
Solid and feeble bases will depend in like manner on whether the response is reversible (there are exemptions to this obviously)
NaOH + H2O - > Na+ + OH-+ H2O
Kb = [Na+] [OH-]/[NaOH]
