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vovangra [49]
4 years ago
6

A Wi-Fi hotspot is an area with an accessible wireless network. The term is most often used to refer to wireless networks in pub

lic areas like airports and coffee shops. Some are free and some require fees for use, but in either case they can be handy when you are on the go. Just like cellphones and televisions, wi-fi works by utilizing ______________ to transmit signals and data. A) radio waves B) microwaves C) ultraviolet rays D) infrared waves
Physics
2 answers:
Scrat [10]4 years ago
6 0

Cellular telephone service, television, garage-door openers, toy walkie-talkies, RC model airplanes and boats, taxi communication, ambulance communication, police communication, fire communication, cordless telephones, wireless headphones, 'microwave' ovens, and Bluetooth stuff, all radio waves to transmit and receive their signals.

None of these use 'microwaves' ... not even 'microwave' ovens.  'Microwave' is a label for radio at frequencies above 3 GHz, and none of these things operate at frequencies that high. Bluetooth and microwave ovens operate around 2.45 GHz.

Wi-Fi has one set of channels around 2.4 GHz ... radio waves but not microwaves.  Wi-Fi also has another set of channels around 5 GHz ... radio waves that can properly also be called 'microwaves'.

Some TV remotes use infrared waves to communicate with the TV set.

We don't (yet ?) manufacture anything that uses ultraviolet rays, X-rays, or gamma rays for communication.  Even if we knew how, these forms of radiation are too dangerous to go shining them around all over the place where people are.

 

fenix001 [56]4 years ago
5 0

Answer:

<h2>A) radio waves</h2>

Explanation:

Wi-Fi is inside the range of radio waves range in the electromagnetic spectrum, just like cellphones and televisions. Basically, this radio waves are the ones that carry all the information through out wifi, just like cellphones calls or messages.

So, basically, radio waves are the medium to transmit signals and data that we call Wi-Fi.

Therefore, the answer is A.

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Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa
anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

Explanation:

Given that,

First charge q_{1}= 2.9\mu C

Second chargeq_{2}= 2.9\mu C

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

E_{1}=\dfrac{kq}{r'^2}

Put the value into the formula

E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}

E_{1}=52200=52.2\times10^{3}\ N/C

For E₂,

Using formula of electric field

E_{1}=\dfrac{kq}{r^2}

Put the value into the formula

E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}

E_{2}=104400=104.4\times10^{3}\ N/C

We need to calculate the horizontal electric field

E_{x}=E_{1}\cos\theta

E_{x}=52.2\times10^{3}\times\cos45

E_{x}=36910.97=36.9\times10^{3}\ N/C

We need to calculate the vertical electric field

E_{y}=E_{2}+E_{1}\sin\theta

E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45

E_{y}=141310.97=141.3\times10^{3}\ N/C

We need to calculate the net electric field

E_{net}=\sqrt{E_{x}^2+E_{y}^2}

Put the value into the formula

E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}

E_{net}=146038.69\ N/C

E_{net}=146.03\times10^{3}\ N/C

We need to calculate the direction of electric field

Using formula of direction

\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}

\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})

\theta=75.36^{\circ}

Hence, The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

4 0
3 years ago
A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom o
Jet001 [13]

Answer:

C) 3,000 kg m/s

Explanation:

We can consider the horizontal velocity of the motorcycle to be zero, since it rolls off the edge of the cliff very slowly. So, we only need to find the vertical velocity at the time of the impact with the ground.

The vertical velocity of the motorcycle at time t is given by (free-fall motion):

v(t)=v_0 -gt

where

v_0=0 is the initial vertical velocity (zero, since the motorcycle is not moving)

g = 9.8 m/s^2 is the acceleration due to gravity

t is the time

Since the motorcycle hits the ground after t = 3 seconds, we have

v(3 s)=0-(9.8 m/s^2)(3 s)=-29.4 m/s

And since we know its mass, m=100 kg, we can find its momentum:

p=mv=(100 kg)(-29.4 m/s)=-2940 kg m/s \cdot -3000 kg m/s

and the negative sign simply means downward direction.

8 0
3 years ago
A small airplane flies 780 miles with an average speed of 260 miles per hour. 1.5 hours after the plane leaves, a Boeing 747 lea
Lera25 [3.4K]

Answer:

520 miles per hour

Explanation:

Let the speed of the Boeing 747 be x miles per hour.

The small airplane covers distance of 780 miles with speed 260 miles per hour.

Also,

After 1.5 hours the Boeing 747 leave the same place and reaches at same time. Both covered distance of 780 miles.

So,

<u>Time taken by Boeing 747 + 1.5 hours = Time taken by small plane.</u>

Also,

Time =  Distance/ speed

So,

780 / x + 1.5 = 780/ 260

Solving for x, we get:

<u>x = 520 miles per hour</u>

6 0
4 years ago
Mountains are part of which earth sphere?? Am I correct?
sammy [17]
You are correct. Mountains are part of the lithosphere.
8 0
3 years ago
Read 2 more answers
Type the correct answer in the box. Spell the word correctly.
serious [3.7K]

Answer:

The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ), which is associated with dark energy and <u>cold dark matter</u>.

^Also works for Plato users.

3 0
3 years ago
Read 2 more answers
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