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4 years ago

⚠️ Please help ⚠️ Which graph best represents the relationship between KE and mass ?

Physics

1 answer:

shusha [124]4 years ago

3 0

Answer:

Graph (A)

Explanation:

The energy that is possessed due to the motion of an object is called its kinetic energy.

The mathematical expression for kinetic energy is given by:

$E_k=\dfrac{1}{2}mv^2$ ........ (1)

Where

m is the mass of the object

v is the velocity with which it is moving

So, from equation (1) it is clear that there is a direct relation between kinetic energy and mass. Greater the mass, more will be its kinetic energy.

So, the graph that represent relationship between mass and kinetic energy is (A).

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Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

Calculate the tension on the rope. A. 57.89 N B. 32.73 N C. 69.84 N D. 12.55 N

Ratling [72]

Hi there!

$\large\boxed{\text{B. 32.73N}}$

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

$a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}$

Plug in values. Let g = 10 m/s²

$a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}$

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

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